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Phantasy [73]
3 years ago
9

F (x)=x^2-14+44 find the x value of the turning point

Mathematics
1 answer:
aniked [119]3 years ago
5 0
So... assuming f(x)=x^2-14x+44 then

 f(x)=x^2-14x+44\implies 
\begin{array}{lccclll}
\boxed{1}x^2&\boxed{-14}x&\boxed{+44}\\
\uparrow &\uparrow &\uparrow\\
a&b&c
\end{array}
\\ \quad \\
\textit{vertex of a parabola}\\ \quad \\
y = {{ \boxed{a}}}x^2{{ \boxed{+b}}}x{{ \boxed{+c}}}\\ \quad \\

\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
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Answer:

Step-by-step explanation:

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