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GenaCL600 [577]
2 years ago
9

Simplify 4√16 + 8√16

Mathematics
1 answer:
Mumz [18]2 years ago
4 0

4\sqrt{16} + 8\sqrt{16}:

Since \sqrt{1} =1, we get:

4\cdot \:1\cdot \:6+8\cdot \:1\cdot \:6=24+48=72

-----------------------------------------------------------------------------------

7\sqrt{4} *3\sqrt{8}

We have \sqrt{4}=2

simplify \sqrt{8} = \sqrt{2^3} = \sqrt{2^2*2}

then the radical rule is used: \quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}

⇒ \sqrt{2^2*2} = \sqrt{2^2} \sqrt{2}= \sqrt{4}\sqrt{2} =2\sqrt{2}

Now we have \sqrt{4}=2 and \sqrt{8}=2 \sqrt{2}

7\sqrt{4} *3\sqrt{8} = 7*2*3*2\sqrt{2} = 84 \sqrt{2}

-----------------------------------------------------------------------------------

2\sqrt{4}+5 \sqrt{9}

2\sqrt{4} =2*2= 4 and 5\sqrt{9} =5*3= 15

2\sqrt{4}+5 \sqrt{9} = 4+15 = 19

-----------------------------------------------------------------------------------

4\sqrt{5} -2\sqrt{5} = 2\sqrt{5}

since 2\sqrt{5} is the half of 4\sqrt{5}

-----------------------------------------------------------------------------------

-4\sqrt{2}\:+\:5\sqrt{2} =1 \sqrt{2} = \sqrt{2}\\    <em>(-4+5=1)</em>

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The tickets for a dance recital cost $5.00 for adults and $2.00 for children. If the total number of tickets sold was 295 and th
dem82 [27]
To solve, you would need to make two equations and substitute one in for the other. Let a = # of adults, and c = # of children

5a + 2c = 1,220
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a + c = 295
-c         -c
a = 295 - c

5(295 - c) + 2c = 1,220
1,475 - 5c + 2c = 1,220
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1,475 - 3c = 1,220
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Hope this helps!
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3 years ago
Is the relation a function? Why or why not?<br><br> {(–3, –2), (–1, 0), (1, 0), (5, –2)}
tankabanditka [31]

Answer:

yes, the given relation is a function.

Step-by-step explanation:

The given relation is

{(–3, –2), (–1, 0), (1, 0), (5, –2)}

A relation is called function if each element of the domain is paired with exactly one element of the range.

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