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xeze [42]
3 years ago
11

The light-independent reactions of photosynthesis, also known as the Calvin cycle, must repeat six times in order for a cell to

have enough material to construct a complete glucose molecule. A variety of molecules are used and produced during this process.Sort the molecules below into three categories; molecules brought in and used in six turns of the Calvin cycle, molecules produced during six turns of the Calvin cycle that leave the cycle, and molecules used and regenerated within the Calvin cycle during six turns.Molecules:a. 10G3P b. CO2 c. 12NADPH d. 18ADP e. 6RuBP f. 2G3P g. 18ATP h. 12NADPH^+ + 12H^+
Biology
1 answer:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

Molecules brought in: 3CO2, 9ATP, 6NADPH

Molecules Produced: 1G3P, 9ADP, 6NADP+ +H+

Molecules used and Regenerated: 3RuBP, 5G3P

Explanation:

1. Molecules brought in and utilized in the light-independent reaction or Calvin cycle:

-CO2 from outside the cell

-Molecules take energy from the light-dependent reactions

2. Molecules produced during the light-independent reaction or Calvin cycle that leave the cycle:

-Energy-carrier molecules that have lost some energy\

-3-carbon molecules that store energy

3. Molecules produced in the cytoplasm from the end products of the Calvin cycle:

-Organic molecules such as glucose

Thus, Molecules brought in: 3CO2, 9ATP, 6NADPH

Molecules Produced: 1G3P, 9ADP, 6NADP+ +H+

Molecules used and Regenerated: 3RuBP, 5G3P

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Assuming that fur color in the mouse is represented by the allele A (a), In order to give 1:1 phenotypic ratio of the offspring, it means the white mouse is heterozygous with Aa genotype and the black mouse is homozygous with aa genotype. Also, it means that the allele A is dominant over the allele a.

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aa = black

Ratio of white to black = 50/50 or 1:1

Hence, in order for a cross to yield only white offspring, the parents can either be homozygous AA and AA or one will be homozygous AA and the other will be heterozygous Aa.

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In order to produce only black offspring, both parents must be homozygous aa.

             aa    x    aa

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