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Fudgin [204]
3 years ago
7

Mary is paid 7.5% commission on all of her sales. She had sales of $2300 for the month of December. How much commission did Mary

make?
Mathematics
1 answer:
Doss [256]3 years ago
5 0

Answer: $172.50

Step-by-step explanation:

$2300 x 0.075 = $172.50

You can double check quickly because you know 10% of 2300 is $230, so 5% is $115.  The answer is halfway between the 5% and 10% numbers, so you know it is reasonable.

You might be interested in
What is the equation of the line that passes through (0, -2) and has a slope of 0? NEED HELP ASAP!!
Molodets [167]
The equation is y= -2.
How? If you recall, a linear equation is y= mx+b. The m is the slope (growth) and b is the y-intercept ( where the line crosses the y-axis).

Now since there is no slope or m, the equation would look like this:
y= b or y= 0+b

Next, you want to input the coordinator points (0, -2) into the equation. reminder: (x, y) = x=0 y= -2

y= 0+ -2
y= -2

And there you go! The equation is y= -2. I hope I help you in solving this problem, if not message me, because I'll be glad to help you.
8 0
3 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e−5t
Elan Coil [88]

Answer:

x = 1 - 5t

y = t

z = 1 - 5t

Step-by-step explanation:

For the equation of a line, we need a point and a direction vector. We are given a point (1, 0, 1).

Since the line is suppose to be a tangent to the given curve at the point (1, 0, 1), we need to find a tangent vector for which the curve passes through that point.

We have x = e^(-5t)cos5t

at t = 1, x = e^(-5)cos5

at t = 0, x = 1

y = e^(-5t)sin5t

at t = 1, y = e^(-5)sin5

at t = 0, y = 0

z = e^(-5t)

at t = 1, z = e^(-5)

at t = 0, z = 1

Clearly, the only parameter value for which the curve passes through the point (1, 0, 1) is t = 0.

In vector notation, the curve

r(t) = xi + yj + zk

= e^(-5t)cos5t i + e^(-5t)sin5t j + e^(-5t) k

r'(t) = [-5e^(-5t)cos5t - e^(-5t)sin5t] i +[e^(-5t)cos5t - 5e^(-5t)sin5t] j - 5e^(-5t) k

r'(0) = -5i + j - 5k

is a vector tangent at the point.

We get the parametric equation from this.

x = x(0) + tx'(0)

= 1 - 5t

y = y(0) + ty'(0)

= t

z = z(0) + tz'(0)

= 1 - 5t

8 0
3 years ago
In a fitness program, Pedro does 20 sit-ups on the first day, and increases this by 2 sit-ups everyday. Determine the day when t
Fittoniya [83]

Answer:

day 540

Step-by-step explanation:

He increases his number of situps by 2 each day meaning on day 1 he'd do 2 extra, on day 2 he'd do 4 extra, on day he'd do 6 extra etc. We can show this by saying +2x where x is the day he is on.  Then since he started with 20 we have to add 20 so it would be 20+2x.  We want to know what day it is when he does 1100 situps so we can set our equation equal to 1100 and solve for X which is the day it would be.

20+2x=1100

2x=1080

I hope this helps and please don't hesitate to ask if there is anything still unclear!

x=540

5 0
3 years ago
-11 - 5x = 6(5x + 4)
gavmur [86]

Answer:

x=-1

Step-by-step explanation:

5 0
3 years ago
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Irina-Kira [14]

It A, C, and E on edge 2020

4 0
3 years ago
Read 2 more answers
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