Answer:
![\frac{1}{ \sqrt[7]{ {12}^{4} } }](https://tex.z-dn.net/?f=%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B7%5D%7B%20%7B12%7D%5E%7B4%7D%20%7D%20%7D%20)
Step-by-step explanation:
![{12}^{ - \frac{4}{7} } is \: the \: same \: as \\ \frac{1}{ {12}^{ \frac{4}{7} } } \\ {12}^{ \frac{4}{7} } can \: also \: be \: expressed \: as \\ \sqrt[7]{ {12}^{4} }](https://tex.z-dn.net/?f=%20%7B12%7D%5E%7B%20-%20%20%5Cfrac%7B4%7D%7B7%7D%20%7D%20is%20%5C%3A%20the%20%5C%3A%20same%20%5C%3A%20as%20%5C%5C%20%20%5Cfrac%7B1%7D%7B%20%7B12%7D%5E%7B%20%5Cfrac%7B4%7D%7B7%7D%20%7D%20%7D%20%20%5C%5C%20%20%7B12%7D%5E%7B%20%5Cfrac%7B4%7D%7B7%7D%20%7D%20can%20%5C%3A%20also%20%5C%3A%20be%20%5C%3A%20expressed%20%5C%3A%20as%20%5C%5C%20%20%5Csqrt%5B7%5D%7B%20%7B12%7D%5E%7B4%7D%20%7D%20)
Therefore:
![{12} ^ { -\frac{4}{7} } \: is \: equivalent \: to \\ \frac{1}{ \sqrt[7]{ {12}^{4} } }](https://tex.z-dn.net/?f=%20%7B12%7D%20%5E%20%7B%20-%5Cfrac%7B4%7D%7B7%7D%20%7D%20%20%5C%3A%20is%20%5C%3A%20equivalent%20%5C%3A%20to%20%5C%5C%20%20%5Cfrac%7B1%7D%7B%20%5Csqrt%5B7%5D%7B%20%7B12%7D%5E%7B4%7D%20%7D%20%7D%20)
Answer:
jdnkwf
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
Just like a rectangle, times one length times width
Answer:
C. (x-2)^2=7
Step-by-step explanation:
What you have to do first is to get rid of the 3 in the x^2 so you will divide 3 by the whole thing to get x^2-4x=3.
You will then divide -4 by 2 and then square the answer to get 4.
You will then add the 4 into the end of the equation and to the 3 to get x^2-4x+4=7.
You will then make into a perfect square (x-2)^2=7 and that is your answer.
