your answer would be 33.
step 1
2(+14)−1(2−5)
2+28−1(2−5)
step 2 distribute
2+28−1(2−5)
2+28−2+5
step 3 then add the numbers
2+28−2+5
2+33−2
combine
2+33−2
ANSWER IS
33
To check which ordered pair (point) is in the solution set of the system of given linear inequalities y>x, y<x+1; we just need to plug given points into both inequalities and check if that point satisfies both inequalities or not. If any point satisfies both inequalities then that point will be in solution.
I will show you calculation for (5,-2)
plug into y>x
-2>5
which is clearly false.
plug into y<x+1
-2<5+1
or -2<6
which is also false.
hence (5,-2) is not in the solution.
Same way if you test all the given points then you will find that none of the given points are satisfying both inequalities.
Hence answer will be "No Solution from given choices".
Answer:
0.5333
Step-by-step explanation:
Please mark 2 brainliests because I need.
Since a^2+b^2=c^2 becomes 20^2+b^2=29^2, we solve for b:
400+b^2=841
b^2=441
b=21
So the length of b is 21 units.
Hope this helped!
