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Natalka [10]
3 years ago
7

Kool-aide is made from flavored powder and water, with the ratio of powder to water 3:2 based on weight. If 120g of flavored pow

der are needed for a certain amount of Kool-aide, how much water will be needed for this amount?
Mathematics
2 answers:
grigory [225]3 years ago
7 0
Add about 1/3 of the <span>water

Hope that helped :)</span>
MAXImum [283]3 years ago
5 0

The given ratio of powder to water is 3:2 based on weight for Kool-aide. It is also given that 120g of flavored powder is needed for a certain amount of Kool-aide.

Let us assume that the amount of water (by weight) required to maintain the given ratio of 3:2 be represented by the letter x. Thus, from the given information we can conclude that:

\frac{Powder Weight}{Water Weight}=\frac{3}{2}=\frac{120}{x}

\therefore \frac{3}{2}=\frac{120}{x}

Cross-multiplying we get:

3x=240

\therefore x=\frac{240}{3}=80 grams.

Thus, the amount of water in grams in that Kool-aide is 80 grams.

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