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alexandr1967 [171]
3 years ago
15

Whether it’s 74.89, 30.29, 38.16 or 66.73

Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0

Let l be the length of one leg, and h be the length of the hypothenuse. Finally, let \alpha be the measure of the angle between them. Then, the following relation holds:

l = h\cos(\alpha)

Plugging your values, we have

34 = x\cos(27)

Solving for x, we have

x = \dfrac{34}{\cos(27)} \approx 38.16

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2-5x=7x-12<br> what is the answer to this solution
Fynjy0 [20]

Answer:

7/6

Step-by-step explanation:

Subtract 2 from both sides and subtract 7 from both sides and get -14/-12x and make the fraction smaller and get 7/6.

4 0
2 years ago
Brooke wants to build a tree house. She wants the tree house to be 3 ft. more than half the height of the tree. If the tree is h
ad-work [718]
The correct answer is A height/2 + 3, basically your saying half the height +3 to the total.
4 0
3 years ago
Read 2 more answers
A rectangle has a height of t^2+7t+6t
jek_recluse [69]

Answer:

2t^3+15t^2+19t+6

Step-by-step explanation:

Height of the Rectangle=t^2+7t+6

Width of the Rectangle=2t+1

Area of the Rectangle = Height X Width

=(2t+1)(t^2+7t+6)\\=2t(t^2+7t+6)+1(t^2+7t+6)\\=2t^3+14t^2+12t+t^2+7t+6\\$Collect like terms\\=2t^3+14t^2+t^2+12t+7t+6\\Area=2t^3+15t^2+19t+6\\

The area of the rectangle is 2t^3+15t^2+19t+6

4 0
3 years ago
2/21 times 7/8 in simplest form
Angelina_Jolie [31]

2/21 * 7/8

14/168

divide top and bottom by 14

1/12

8 0
2 years ago
An insurance company has 25,000 automobile policy holders. If the yearly claim of a policy holder is a random variable with mean
telo118 [61]

Answer:

P(T>8300000)=1-P(T

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Data given

n = 25000 represent the automobile policy holders

\mu= 320 represent the population mean

\sigma =540 represent the population standard deviation

Let T the variable that represent the total of interest on this case. We can assume that the random variable for an individual policy holder is given by:

X\sim N(\mu = 540, \sigma=540)

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

Solution to the problem

First we need to find the distribution for the random variable T like this:

\bar X = \frac{\sum_{i=1}^n x_i}{n}

And the total T is given by:

T=\sum_{i=1}^n X_i =n \bar X

We can find the expected value, variance and deviation for this random variable like this:

E(T)= n E(\bar X) = n \mu = 25000*320=8000000

Var(T)= Var(n\bar X)= n^2 Var(\bar X) = n^2 \frac{\sigma^2}{n}=n \sigma^2 =25000*(540^2)=7290000000

Sd(T)=\sqrt{7290000000}=85381.497

And we are interested on this probability:

P(T>8300000)

And we can use the Z score formula given by:

Z=\frac{T-E(T)}{\sigma_T}

P(T>8300000)=1-P(T

6 0
3 years ago
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