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Irina18 [472]
4 years ago
10

Mr. Wilkins deposited $2,500 in a new account at his bank.

Mathematics
1 answer:
MAXImum [283]4 years ago
5 0

$2835.56 is the closest amount to the balance of the account at the

end of 2 years

Step-by-step explanation:

The formula for compound interest, including principal sum is

A=P(1+\frac{r}{n})^{nt} where:

  • A is the future value of the investment/loan, including interest
  • P is the principal investment amount (the initial deposit or loan amount)
  • r is the annual interest rate (decimal)
  • n is the number of times that interest is compounded per unit t
  • t is the time the money is invested or borrowed for

Mr. Wilkins deposited $2,500 in a new account at his bank.  

The bank pays 6.5% interest compounded annually on this account.

Mr. Wilkins makes no additional deposits or withdrawals

We need to find the closest amount to the balance of the account at

the end of 2 years

∵ P = $2,500

∵ r = 6.5% = (6.5/100) = 0.065

∵ n = 1 ⇒ compounded annually

∵ t = 2

Substitute all of these value in the formula above to find A

∵ A=2,500(1+\frac{0.065}{1})^{(1)(2)}

∴ A=2,500(1.065)^{2}

∴ A = $2835.56

$2835.56 is the closest amount to the balance of the account at the

end of 2 years

Learn more:

You can learn more about interest in brainly.com/question/11149751

#LearnwithBrainly

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The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1
snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is<em> </em>\\ P(V \cup M) = 0.88. (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)

We already know from the question the following probabilities:

\\ P(V) = 0.73

\\ P(M) = 0.18

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

\\ P(V \cap M) = 0.03

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as \\ P(V \cup M) or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)

\\ P(V \cup M) = 0.73 + 0.18 - 0.03

\\ P(V \cup M) = 0.88

Then, <em>the probability that a student has either a Visa card </em><em>or</em><em> a MasterCard is </em>\\ P(V \cup M) = 0.88.<em> </em>

Are the events V and M independent?

A way to solve this question is by using the concept of <em>conditional probabilities</em>.

In Probability, two events are <em>independent</em> when we conclude that

\\ P(A|B) = P(A) [1]

The general formula for a <em>conditional probability</em> or the probability that event A given (or assuming) the event B is as follows:

\\ P(A|B) = \frac{P(A \cap B)}{P(B)}

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

\\ P(M|V) = \frac{P(M \cap V)}{P(V)}

\\ P(M|V) = \frac{0.03}{0.73}

\\ P(M|V) \approx 0.041

If M were independent from V (according to [1]), we have

\\ P(M|V) = P(M) = 0.18

Which is different from we obtained previously;

That is,

\\ P(M|V) \approx 0.041

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

\\ P(V|M), as follows:

\\ P(V|M) = \frac{P(V \cap M)}{P(M)}

\\ P(V|M) = \frac{0.03}{0.18}

\\ P(V|M) = 0.1666.....\approx 0.17

Which is different from

\\ P(V|M) = P(V) = 0.73

In the case that both events <em>were independent</em>.

Notice that  

\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)

\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03

\\ 0.03 = 0.03 = 0.03 = 0.03

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Can somebody help me asap
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Answer:

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Can y'all help please? and please explain. thxx!
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Answer:


Step-by-step explanation:7c

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