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stepan [7]
4 years ago
9

A car salesman sells cars with prices ranging from $5,000 to $45,000. The histogram shows the distribution of the numbers of car

s he expects to sell over the next 10 years. What is the median of the car price range?
Mathematics
1 answer:
iogann1982 [59]4 years ago
8 0
It's either 20 or 25 thousand.
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The ratio of money in Obi's wallet to Rudy's wallet one day was 5:2.
mamaluj [8]

Answer:

The amount that Obi initially had was £20

Step-by-step explanation:

Let

x ----> amount that Obi initially has

y ----> amount that Rudy has

we know that

\frac{x}{y} =\frac{5}{2}

x=2.5y ----> equation A

x-20=y-8

y=x-20+8

y=x-12 ----> equation B

Solve the system by substitution

substitute equation A in equation B

y=(2.5y)-12

solve for y

2.5y-y=12\\1.5y=12\\y=8

Find the value of x

x=2.5(8)=20

therefore

The amount that Obi initially had was £20

4 0
4 years ago
Convert 12 kg to pounds used 1 kg ≈ 2.2 lb.
puteri [66]
12 kg=12*2.2=26.4 pounds

3 0
3 years ago
National data in the 1960's showed that about 44% of the adult population had never smoked cigarettes. In 1995 a national health
Marta_Voda [28]

Answer:

a) 0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487

0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553

The 95% confidence interval would be given by (0.487;0.553)

b) After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated  proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Solution to the problem

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.52 - 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.487

0.52 + 1.96\sqrt{\frac{0.52(1-0.52)}{881}}=0.553

The 95% confidence interval would be given by (0.487;0.553)

Part b

After see the confidence interval we see that the lower limits 0.487>0.44 with 0.44 or 44% the estimated  proportion for 1960, we can conclude that we have a significant increase in the adult proportion had never smoked cigarettes at 5% of significance.

4 0
4 years ago
HELPPPPPP PLSSSS HURRY!
Aleks [24]

Answer:

i think it's A

Step-by-step explanation:

4 0
3 years ago
Write the following statement as a unit rate: 18 laps in 6 minutes
tatuchka [14]

Answer:

3 laps per minute

Step-by-step explanation:

Take the number of laps and divide by the minutes

18/6 = 3 laps per minute

6 0
3 years ago
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