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rusak2 [61]
3 years ago
7

I need help with this answer

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0
And I need help with my gradez
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a cable installer charges $42.50 per hour plus a $60.00 service charge your fathers firm hires him to hook up his companys inter
denis23 [38]
$208.75 because $42.50 x 3.5= 148.75 but you have to add the 60 so 148.75+60=208.75 I hope this helps, if not, I can explain more.
6 0
3 years ago
If x=2/3 and x=-3 are the roots of the equation ax^2+7x+b=0 find the values of a and b
Gnesinka [82]

<u>ANSWER:  </u>

If x = \frac{2}{3} and x = -3 are the roots of the equation, then values of a and b are 3, -6

<u>SOLUTION: </u>

Given, quadratic equation is a x^{2}+7 x+b=0 and its roots are -3 , \frac{2}{3}

We know that, for any quadratic equation of form a x^{2}+b x+c=0 with roots x_{1} and x_{2} then,

Sum of roots (x_{1} +x_{2}) = \frac{-b}{a}

Product of roots ( x_{1} \times x_{2}) = \frac{c}{a}

Now, for given quadratic equation x_{1} = -3 and x_{2} = \frac{2}{3}

hence Sum of roots = \frac{-7}{a}

x_{1} + x_{2} = \frac{-7}{a}

-3 + \frac{2}{3} = \frac{-7}{a}

on solving we get "a" = 3

Now product of roots = x_{1} \times x_{2} = \frac{b}{3}

-3 \times \frac{2}{3} = \frac{b}{3}

b = -6

hence, the values of a and b are 3, -6.

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4 years ago
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olga2289 [7]

Answer:

24. 18.2360564556

Step-by-step explanation:

i don't have any thing

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What is the square root of 64y^16?
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8y^8. Square root of 64 is 8 and for exponents you divide by 2 to find its square root
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the domain: no real numbers so its  negative infinity, positive infinity  

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