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3 years ago

Pls help me with Geometry I will give good reward+good rating if correct

Mathematics

1 answer:

pav-90 [236]3 years ago

8 0

Step-by-step explanation:

is they're any pictures that go with these?

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Solve: -8r - (-2r-3) = 13 (if you can give a step by step, that would be great!)

coldgirl [10]

Answer:

$r = - \frac{5}{3} = 1 \frac{2}{3} = - 1.6$

Step-by-step explanation:

$- 8r - ( - 2r - 3) = 13$

$- 8r + 2r + 3 = 13$

$- 6r + 3 = 13$

$- 6r = 13 - 3$

$- 6r = 10$

$\boxed{\green{r = - \frac{5}{3} = 1 \frac{2}{3} = - 1.6}}$

4 0

3 years ago

30 points! please help

Trava [24]

Gopherus have been clocked at rates 0.13 to 0.30 mph (0.05 to 0.13 m/s

5 0

3 years ago

Factor the expression over the complex numbers. x2+50

Karo-lina-s [1.5K]

X^2 + 50

√x^2+ √50

x + 5√2

5√2 = ~7.07106

x + 7.07106

x = -7.07106

hope this helps

8 0

3 years ago

What values of c and d make the equation true?

saul85 [17]

Answer:

Third option.

Step-by-step explanation:

You need to cube both sides of the equation. Remember the Power of a power property:

$(a^m)^n=a^{mn$

$\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d})\\\\(\sqrt[3]{162x^cy^5})^3=(3x^2y(\sqrt[3]{6y^d}))^3\\\\162x^cy^5=27x^6y^36y^d$

According to the Product of powers property:

$(a^m)(a^n)=a^{(m+n)$

Then. simplifying you get:

$162x^cy^5=162x^6y^{(3+d)}$

Now you need to compare the exponents. You can observe that the exponent of "x" on the right side is 6, then the exponent of "x" on the left side must be 6. Therefore:

$c=6$

You can notice that the exponent of "y" on the left side is 5, then the exponent of "x" on the left side must be 5 too. Therefore "d" is:

$3+d=5\\d=5-3\\d=2$

4 0

3 years ago

Factor completely 3x2 + y. x(3x + y) y(3x2) xy(3x + 1) Prime

Rainbow [258]

Answer:

Option (d) is correct.

The given polynomial $3x^2+y$ is a prime polynomial.

Step-by-step explanation:

Given : $3x^2+y$

We have to factorize it completely.

Since , factorization is the process of reducing a given polynomial into a lower degree polynomial by taking common factors out into the simplest form.

Consider the given polynomial $3x^2+y$

Since the given polynomial do not have any term common in both terms .

So we cannot factorized it further.

So, the given polynomial $3x^2+y$ is a prime polynomial.

Thus, Option (d) is correct.

5 0

3 years ago

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