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4 years ago

Pls help me with Geometry I will give good reward+good rating if correct

Mathematics

1 answer:

pav-90 [236]4 years ago

8 0

Step-by-step explanation:

is they're any pictures that go with these?

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What is the value of b - c if a = 18, b= 27, and c= 11? O 16 O 11 0 9 0 29

pentagon [3]

Answer: 16

Step-by-step explanation: 27-11=16

4 0

3 years ago

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I need help

damaskus [11]

Answer:

Step-by-step explanation:

6 0

3 years ago

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

3 years ago

A 3 cm 2 cm rectangle sits inside a circle with radius of 4 cm.

Ipatiy [6.2K]

Answer:

44.24 cm squared

Step-by-step explanation:

3.14*4^2=50.24

3*2=6

50.24-6=44.24

hope this helps

7 0

3 years ago

At a school, 40% of the sixth-grade students said that hip-hop is their favorite kind of music. If 100 sixth-grade students pref

HACTEHA [7]

Answer:

250 students

Step-by-step explanation:

Another way of saying this is:

40% of all six-grade students are 100 of them.

So,

40% of total is equal to 100

We can translate this into an algebraic equation and solve for the total number of students.

Let total number of students be "t"

Also, note "of" means "multiplication" and "is" means "equal"

Lets translate word equation to algebraic:

"40% of total is equal to 100"

40% * t = 100

Converting percentage to decimal by dividing by 100, we have:

40% = 40/100 = 0.4

Now, we have:

0.4 * t = 100

We can now solve for t:

$0.4 * t = 100\\t=\frac{100}{0.4}\\t=250$

Hence,

the total number of students is 250

4 0

3 years ago

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