Answer:
99.38
Step-by-step explanation:
the area of all the circles by using the formula A=ℼr2 then filling in r with 3.2 A=ℼ3.22=32.2
Knowing that one circle is 32.2 4 circles would have an area of 128.8
Two circles have a combined length and height of 12.8 because the circumference of one circle is 6.4 so two circles reach the sides of the square. So all the sides of the square are 12.8. So finding the area of the square knowing what the sides are, so the area is a=163.84. To find the shaded area you subtract the volume of the square to volume of all 4 circles which is 163.84-128.8 which equals 35.04. Then you find the volume of the semi circle which is 64.34. Then the combination of both shaded regions is 99.38
Plug in a -20 wherever you see a b
(-20)^2 +4*-20-89/13
400 + -80-89/13
400 - 169/13
400-13
=387
Hope this helps
Answer:
B. More than one quadrilateral exists with the given conditions, and all instances must be isosceles trapezoids.
Step-by-step explanation:
In a parallelogram, adjacent angles are supplementary. They are only congruent if the parallelogram is a rectangle. In this problem, adjacent angles are both congruent and acute. If this were a triangle, it would guarantee the triangle is isosceles.
The fact that opposite angles are supplementary guarantees that the fourth side of the figure is parallel to the base between the acute angles. That makes the figure an isosceles trapezoid. Unless specific angles and side lengths are specified, the description matches <em>any</em> isosceles trapezoid.
Answer:
24.73
Step-by-step explanation:
1/3=.33
2/5=.40
0.40+0.33=0.73
16+8=24
24.73