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ozzi
3 years ago
15

Is 10/5 bigger then 21/6

Mathematics
2 answers:
nlexa [21]3 years ago
3 0

Answer:

21/6 is bigger because it's 3.5 and 10/5 is 2

Contact [7]3 years ago
3 0

Answer:

21/6 is bigger because of fractions

Step-by-step explanation:

because of fractions

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Jason bought a car for $12500. According to the insurance company, the value of the car depreciates by 7% each year. What will t
Orlov [11]

Answer:

8696.10

Step-by-step explanation:

If a car depreciates by 7% each year, this means that 7% of its value that year is subtracted from its previous value. In other words, you can multiply its value by (1-0.07)=0.93.

12500\cdot 0.93^5\approx 8696.10. Hope this helps!

3 0
3 years ago
The ratio of bous to girls in the school is 1 to 4. If there are 20 girls, how many boys are there?
anyanavicka [17]

if there's 1 boy to every 4 girls, there's going to be 5 boys for every 20 girls

6 0
4 years ago
Read 2 more answers
Solve for x
Mademuasel [1]

Answer:

x = 9

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)}

Given

11^{x} = 11^{4} × 11^{5} = 11^{(4+5)} = 11^{9}

Since the bases on both sides are common, then equate the exponents

x = 9

4 0
3 years ago
Which number is such that when it's ÷ 27 30 or 45 the remainder is always three​
rewona [7]

Answer:

closest answer = 81

Step-by-step explanation:

81/27 = 3

81/30= 2.7

81/45 = 1.8

6 0
3 years ago
State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle
DENIUS [597]

Answer:

The interval notation for the domain is [\frac{23}{3},\infty  ].

Step-by-step explanation:

Consider the provided information.

It is given that \:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7

We need to find the value of f\left(g\left(x\right)\right).

Put the value of g(x) in  f\left(g\left(x\right)\right).

f\left(g\left(x\right)\right)=f(x-7)  ....(1)

Now, put x=x-7 in \:f\left(x\right)=\sqrt{3x-2}

\:f\left(x-7\right)= \sqrt{3(x-7)-2}

\:f\left(x-7\right)= \sqrt{3x-21-2}

\:f\left(x-7\right)= \sqrt{3x-23}

From equation 1.

f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}

The domain of the function is the set of input values for which a function is defined.

Here, the value of 3x-23 should be greater or equal to 0 as the square root of a negative number is not real.

Domain= 3x-23\geq0

x\geq\frac{23}{3}

The value of x is all real number greater than \frac{23}{3}.

Hence, the interval notation for the domain is [\frac{23}{3},\infty  ].

7 0
3 years ago
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