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3 years ago

Write the equation 2x – 3y = 16 in slope-intercept form.

Mathematics

1 answer:

vodka [1.7K]3 years ago

7 0

Answer: y=2/3x-16/3

Step-by-step explanation:

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Solve please I’m trying to find out if it’s 1/20 or 5/4

kotegsom [21]

Answer:

I’m pretty sure it’s 5/4

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How do you find the sum of cube ?

SIZIF [17.4K]

Answer:

$(2x+5)(4x^{2} -10x+25)=0$

Step-by-step explanation:

Given:

The given equation is.

$8x^{3} +125=0$

Find the some of cube.

Solution:

$8x^{3} +125=0$

$2^{3}x^{3} +5^{3}=0$

$(2x)^{3} +5^{3}=0$ ----------(1)

The sum of the cube formula is given below.

$(a^{3} +b^{3})=(a+b)(a^{2} -ab+b^{2} )$ -----------(2)

By comparing equation 1 and equation 2

$a=2x, b=5$

substitute a and b value in equation 2

$((2x)^{3} +5^{3})=(2x+5)((2x)^{2} -(2x)(5)+5^{2})$

$((2x)^{3} +5^{3})=(2x+5)(4x^{2} -(10x)+25)$

$((2x)^{3} +5^{3})=(2x+5)(4x^{2} -10x+25)$

Therefore the sum of the cube $(2x+5)(4x^{2} -10x+25)=0$

4 0

3 years ago

-1/2 +2=-x+7 how do you figure this out

Feliz [49]

Answer:

x = 5.5

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

$-\frac{1}{2} +2=-x+7$

$-\frac{1}{2} +2= 1.5$

$1.5=-x+7$

-7 -7

$-5.5 = -x$

Divide both sides by -1.

$5.5 = x$

3 0

3 years ago

A town has a population of 18000 and grows at 2% every year. To the nearest tenth of a year, how long will it be until the popul

8090 [49]

Answer:

19.9

Step-by-step explanation:

we can write the following equation

18000(1.02)^n

where n is the number of years

so we have

26700=18000(1.02)^n

solve for n

1.483=1.02^n

use logs to solve for n

n=19.9

8 0

3 years ago

The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.

Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

$\overline{CD} = 12 \: units$

$\overline{C'D'}$

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

$\overline{C'D'} = n \times \overline{CD}$

Option A

If n=3/2, then

$\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units$

This is true.

Option B

If n=4, then

$\overline{C'D'} = 4 \times 12 = 36 \: units$

This is false.

Option C

If n=8, then

$\overline{C'D'} = 8 \times 12 = 96 \: units$

This too is false.

Option D

If n=2, then

$\overline{C'D'} = 2 \times 12 = 24 \: units$

This is true

Option E

If n=3/4, then

$\overline{C'D'} = \frac{3}{4} \times 12$

$\overline{C'D'} = 3 \times 3 = 9 \: units$

This is also true.

4 0

3 years ago