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3 years ago

What is the slope of the graph?

Mathematics

1 answer:

Ivahew [28]3 years ago

6 0

The slope is 5/1 because b =5

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There is a bag filled with 4 blue and 5 red marbles. A marble is taken at random fròm the bag,the colour is noted and then is re

atroni [7]

Hi there!

Answer:

1/6

Explanation:

The first probability of getting blue is 4 out of the total marbles so 4/9.

The second time there are only 3 blue marbles out of 8 now so 3/8.

So the answer is 4/9X3/8

which equals 12/72 or 1/6

Hope this helps!

7 0

3 years ago

Can anyone help me with my math homework please

Delvig [45]

125 goes to 5^3, 5^2 goes to (3+2) x 5, and 50 stays the same.

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3 years ago

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Find the unknown side or angle as indicated.<br> Round each side length to the nearest tenth

Rainbow [258]

SOLVE THE EQUATIONS

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3 years ago

Wats the answer plzzzzzz quick

Vadim26 [7]

(a) With a unit rate of 8, repeated (iterated) 72 times, we can simply multiply 8 by 72 to get the net change: 8 × 72 = 576 fish.

(b) For the unit rate (i.e. rate of change per time - minutes in this case) we can simply divide the total water pumped out by the total time it took to perform this. So: 48 ÷ 8 = 6 gallons/min.

Hope I could help you! :)

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3 years ago

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Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

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3 years ago