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Lesechka [4]
2 years ago
15

Jason hypothesized that exercise would result

SAT
2 answers:
harkovskaia [24]2 years ago
7 0
That his body would be using more oxygen during his exercise.
masha68 [24]2 years ago
5 0
his body will be using more oxygen
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This excerpt connects to the theme "evil can never truly hide itself" because it shows how jekyll makes hyde insanely angry. Hyd
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The given excerpt connects to the theme "evil can never truly hide itself" because; B: Hyde continuously plagues jekyll.

<h3>Story on Strange Case of Dr. Jekyll and Mr Hyde</h3>

The given excerpt is taken from the novel titled "Strange Case of Dr. Jekyll and Mr Hyde" written by a Scottish author named Robert Louis Stevenson.

From the excerpt we see that Utterson and Enfield are horrified when they see Jekyll's transformation. We also see where it was said that "We have come too late," he said sternly, "whether to save or punish. Hyde is gone to his account; and it only remains for us to find the body of your master."

Finally, we can conclude that the way the excerpt connects to the theme "evil can never truly hide itself" is that Hyde continuously plagues jekyll.

Read more about Strange Case of Dr. Jekyll and Mr Hyde at; brainly.com/question/6330517

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The Hardy Weinberg equation is defined as p squared plus two p Q plus Q Squared equals one, and this equation is used to determine if evolution is occurring in a particular population. So P is defined as the dominant Ulliel frequency and cue is defined as the recess of illegal frequency. So if one of these illegal frequencies is given, we can easily find the frequency value for the other a wheel. So let's say that the dominant frequency, the dominant Ulliel here, is defined as a one. We have another legal called a two, so let's say a one is given. So to find a to all we need to dio so a two frequency would be equal toe one minus a one. And once we have the value of A to we can determine the hetero zegas frequency by solving this part of the equation. So we would just do two times a one times a two, and that would give us the frequency of the hetero Zika's individuals. Okay,

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