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SpyIntel [72]
3 years ago
9

Solve for x. (х-4)(х - 4) = 0 ОА. -16 ОВ. -4 Ос. Op. 16

Mathematics
1 answer:
Stolb23 [73]3 years ago
5 0

Answer:

A

Step-by-step explanation:

You might be interested in
5.
stellarik [79]

Answer:

c.

Step-by-step explanation:

Move the constant to the right side and the sign

0.5x=26-6

Calculate

0.5x=26-6=20 >>> 0.5x=20

divide both sides of by the equation 0.5

0.5x=20 >>> x=40

4 0
4 years ago
What is the principal solution to the equation?
ikadub [295]
First step: x= ± √ 121
Second step and correct answer: x= ± 11

Because: x^2 = x= ± √
6 0
3 years ago
Find the constant of proportionality for b) y=2x
natima [27]

Answer:

The constant of proportionality is 2.

Step-by-step explanation:

In an equation for which we are looking for the constant of proportionality, we use the base form below.

y = kx

In which k is the constant of proportionality. If we use the equation given

y = 2x

We can see k = 2

8 0
3 years ago
Jayden and Derek go to Chipotle. Jayden gets a burrito for $7.49 and Derek gets a lifestyle bowl for $8.29. They each get a drin
madam [21]

Answer:

$18.97

Step-by-step explanation:

Add $7.49, $8.29, and $1.79 together= $17.57.

Then, add the 8% tax. So $17.57+8% of tax= $18.97.

3 0
3 years ago
What are the possible rational roots of the polynomial equation?<br><br> 0=2x7+3x5−9x2+6
RoseWind [281]

Answer: \pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

Step-by-step explanation:

We can use the Rational Root Test.

Given a polynomial in the form:

a_nx^n +a_{n- 1}x^{n - 1} + … + a_1x^1 + a_0 = 0

Where:

- The coefficients are integers.

- a_n is the leading coeffcient (a_n\neq 0)

- a_0 is the constant term a_0\neq 0

Every rational root of the polynomial is in the form:

\frac{p}{q}=\frac{\pm(factors\ of\ a_0)}{\pm(factors\ of\ a_n)}

For the case of the given polynomial:

2x^7+3x^5-9x^2+6=0

We can observe that:

- Its constant term is 6, with factors 1, 2 and 3.

- Its leading coefficient is 2, with factors 1 and 2.

 Then, by Rational Roots Test we get the possible rational roots of this polynomial:

\frac{p}{q}=\frac{\pm(1,2,3,6)}{\pm(1,2)}=\pm\frac{1}{1}, \pm\frac{1}{2},\pm\frac{2}{1},\pm\frac{3}{1}, \pm\frac{3}{2}

5 0
3 years ago
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