<span>π = C / 10 ( the is 10 because diameter = 2 * radius)</span>
Hello!
Angle POQ and angle MON are vertical which means they are congruent
x - 28 = 149
Add 28 to both sides
x = 177
Angle NOQ and angle NOM are supplementary meaning they add to 180
NOQ + NOM = 180
Put in the known angle
NOQ + 149 = 180
Subtract 149 from both sides
NOQ = 31
The answers are x = 177 and angle NOQ = 31
Hope this helps!
Answer:
As we can see the domain is the:"number of minutes water has been added". And from the information given the values for T are between 0 and 60 so then the set of values would be "the set of all real numbers from 0 to 60", and we start from 0 because the time can't be negative.
For the range who represent "amount of water in the pond (in liters)" we need to analyze the possible values for W, since T is defined between 0 and 60 the limits for W are:


So then the set of values for the range are "the set of all real numbers from 300 to 2400" liters.
Step-by-step explanation:
Assuming this complete problem: "The owners of a recreation area are filling a small pond with water. Let W be the total amount of water in the pond (in liters). Let T be the total number of minutes that water has been added. Suppose that
gives as a W function of during the next 60 minutes.
Identify the correct description of the values in both the domain and range of the function. Then, for each, choose the most appropriate set of values.
"
Solution to the problem
As we can see the domain is the:"number of minutes water has been added". And from the information given the values for T are between 0 and 60 so then the set of values would be "the set of all real numbers from 0 to 60", and we start from 0 because the time can't be negative.
For the range who represent "amount of water in the pond (in liters)" we need to analyze the possible values for W, since T is defined between 0 and 60 the limits for W are:


So then the set of values for the range are "the set of all real numbers from 300 to 2400" liters.
Use the PEMDAS method
-solve equation in parentheses
-solve exponents
-solve multiplication
-solve division
-solve addition then subtract