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Answer:
C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Step-by-step explanation:
Given:
Quadrilateral is a parallelogram.
RS║VT; RT is an transversal line;
Hence By alternate interior angle property;
∠SRT≅∠VTR
∠STR≅∠VRT
Now in Δ VRT and Δ STR
∠SRT≅∠VTR (from above)
segment RT= Segment RT (common Segment for both triangles)
∠STR≅∠VRT (from above)
Now by ASA theorem;
Δ VRT ≅ Δ STR
Hence the answer is C. ∠SRT≅∠VTR and ∠STR≅∠VRT
Answer:
28+28=56 so 28 and 28 and the bottom will be 56
Step-by-step explanation:
x²+3x+4=0
x²+3x_ +2=0
x²+3x_2=-2
x²+3x_2+(3x_4)²=-2+(3/4)²
(x+3/4) =-2+9_16
x+3_4 = -32+9__16 =√-23_6
x+3_4 =-√23_4
x = -3+√-23___4
x = -3- √-23___4 , -3+√-23___4 //
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