Triangle Area Formula:
0.5 * Base * Height
SO,
0.5 * 10 * Height = 45.5
5 * Height = 45.5
Height = 9.1
Answer:
Step-by-step explanation:
Given:
Let's substitute -3 for 
Now, let's solve
Hope this helps
First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O.
m∠O = 2 (65°) = 130°
Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°.
m∠O + m∠C + m∠B + m∠A = 360°
Substituting the known values,
130° + 90° + 90° + m∠A = 360°
The value of m∠A is equal to 50°.
<em>Answer: 50°</em>
The correct answer is: x ≥1
Answer:
94.2 in squared
Step-by-step explanation:
lateral area plus area of both flat sides
37.68 + 2(3.14*3^2)
37.68 + 56.52 = 94.2 in squared
