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frosja888 [35]
4 years ago
8

Multiply (1/2)(2x)(x+8)

Mathematics
1 answer:
Lina20 [59]4 years ago
7 0

\bf \left( \cfrac{1}{~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~} \right)(~~\begin{matrix} 2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~x)(x+8)\implies x(x+8)\implies x^2+8x

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Answer:

0.3333 = 33.33% probability that this red ball is from box A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Red ball

Event B: From box A.

Probability of a red ball:

3/10 = 0.3 of 1/2 = 0.5(box A)

6/10 = 0.6 of 1/2 = 0.5(box B). So

P(A) = 0.3*0.5 + 0.6*0.5 = 0.45

Probability of a red ball from box A:

0.3 of 0.5, so:

P(A \cap B) = 0.3*0.5 = 0.15

What is the probability that this red ball is from box A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.15}{0.45} = 0.3333

0.3333 = 33.33% probability that this red ball is from box A.

8 0
3 years ago
The nth term of a sequence is represented by 3n4−10/6n4+7 . What is the limit of the the nth term as n becomes increasingly larg
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Answer:

<h3>1/2</h3>

Step-by-step explanation:

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\lim_{n \to \infty} \frac{3n^4/n^4-10/n^2}{6n^4/n^4+7/n^4}\\= \lim_{n \to \infty} \frac{3-10/n^2}{6+7/n^4}\\= \frac{3-10/(\infty)^2}{6+7/(\infty)^4}\\= \frac{3-0}{6-0}\\= \frac{3}{6}\\ = \frac{1}{2}\\

Hence the limit of the the nth term as n becomes increasingly large is 1/2

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3 years ago
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Step-by-step explanation:

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