Answer:
261∠36° Newtons
Step-by-step explanation:
A straightforward way to find the resultant is to add the x- and y-components of the forces:
r = 300(cos(-30°), sin(-30°)) +180(cos(45°), sin(45°)) +250(cos(135°), sin(135°))
= (300√3/2 +180√2/2 -250√2/2, -300/2 +180√2/2 +250√2/2)
= (150√3 -35√2, -150 +215√2)
≈ (210.310, 154.056)
≈ 260.698∠36.22°
The resultant is approximately 261 Newtons at an angle of 36°.
_____
From components (x, y), the angle is found as arctan(y/x). The magnitude is found as √(x²+y²).
Answer: 2n + 2 should be your answer
Answer:
8.8
Step-by-step explanation:
PEMDAS
5 + 39 /5 = 44/5 = 8.8
Answer:
1) yes
2) No
3) No
4) yes
5) No
Step-by-step explanation:
1) f(0)=0, f(1)=1, f(2)=2, f(3)=3, then ![f[\{0, 1, 2, 3\}]=\{0, 1, 2, 3\}](https://tex.z-dn.net/?f=f%5B%5C%7B0%2C%201%2C%202%2C%203%5C%7D%5D%3D%5C%7B0%2C%201%2C%202%2C%203%5C%7D)
2) f(0)=0, 
, then f(1)=1; 
, then f(2)=0; 
, then f(3)=1
Then ![f[\{0, 1, 2, 3\}]=\{0, 1, 3\}](https://tex.z-dn.net/?f=f%5B%5C%7B0%2C%201%2C%202%2C%203%5C%7D%5D%3D%5C%7B0%2C%201%2C%203%5C%7D)
, this means that f isn't onto.
3.
, then f(1)=0
, then f(2)=2
, then f(3)=2
Then ![f[\{0, 1, 2, 3\}]=\{0, 2\}](https://tex.z-dn.net/?f=f%5B%5C%7B0%2C%201%2C%202%2C%203%5C%7D%5D%3D%5C%7B0%2C%202%5C%7D)
, this means that f isn't onto.
4. ![f[\{0, 1, 2, 3\}]=\{0, 1, 2,3\}](https://tex.z-dn.net/?f=f%5B%5C%7B0%2C%201%2C%202%2C%203%5C%7D%5D%3D%5C%7B0%2C%201%2C%202%2C3%5C%7D)
, then f is onto.
5. ![f[\{0, 1, 2, 3\}]=\{1, 2\}](https://tex.z-dn.net/?f=f%5B%5C%7B0%2C%201%2C%202%2C%203%5C%7D%5D%3D%5C%7B1%2C%202%5C%7D)
, this means that f isn't onto.
