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-Dominant- [34]
3 years ago
15

Hannah claims that 3 is not a rational number because it is not written as a ratio of integers. Is she correct? Explain why or w

hy not.
Mathematics
1 answer:
yanalaym [24]3 years ago
5 0

\bf 3\implies \cfrac{3}{1}\impliedby \textit{ratio of 3 and 1}\implies rational\qquad \checkmark

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27 vector mechanics for engineers volume 11 answer
astra-53 [7]
I think its missing info?
4 0
3 years ago
Katrina drinks 0.5 gallons of water per day. Which expression shows how to find the number of cups of water she drinks in a
Hunter-Best [27]

Answer:

Well the options are not copy pasted properly so im just gonna answer the question

Step-by-step explanation:

1 Gallon contains 16 cups,

so 16 cups for 1 day

so for 7 days,

    No. of cups = 7 x 16 = 112

so the expression would be,

16 cups x 7 days

7 0
3 years ago
John bought a used truck for $4,500. He made an agreement with the dealer to put $1,500 down and make payments of $350 for the n
butalik [34]
The price of the truck is 4500 dollars. 
But he paid it into breakdown:
=> 1500 dollars first payment
=> 350 dollars = 10 months => 350 * 10 = 3500 dollars
=> Total = 3500 + 1500 = 5000 dollars
=> 5000 - 4500 = 500 dollars additional for 10 months
=> 500 / 10 = 50 dollars per month
=> 50 * 12 = 600 dollars for 1 year
=> 600 / 4500 = 13.33% of the yearly interest.
4 0
4 years ago
Let h be the function that assigns each student ID number to a grade level.
denis-greek [22]

Answer:

It is a function Jonny!

Step-by-step explanation:

Hello! I would say to Jonny:

Jonny! A function is a relation between two sets, in which every element of the first set (domain) is assigned only one element of the second set (codomain).

If you have serveral elements of the first set with the same corresponding element of the second set it is correct to call that relation a function.

However, if you have an element of the first set for which your relation can relate to more than one element of the second set, then Jonny, that is not a function.

In the present case, every student ID number can only be realted to a number of the set {9, 10, 11, 12}, a student cannot have more than one current grade level. Therefore, that relation is in fact a function

5 0
3 years ago
Matching Functions
Ainat [17]

Answer:

Graph A → Equation A → Table B → Property D

Graph D → Equation B → Table A → Property B

Graph B → Equation C → Table C → Property E

Graph C → Equation D → Table E → Property A

Graph E → Equation E → Table D → Property C

Step-by-step explanation:

Graph A corresponds to equation A, x·y = 2, and Table B → Property D

xy = 2 has a vertical asymptote at x = 0, and a horizontal asymptote at y = 0

y = 2/x, when x = 0, y = ∞

Graph D corresponds to equation B, -\left |  x\right | + 1 which corresponds to table A → Property B

The domain extends from (-∞, ∞), and [1, -∞)

Graph B corresponds to equation C, -(x + 2)² which gives the values in Table C and Property E wich is a horizontal shift of 2 units left and a reflection across the x-axis

Graph C corresponds to equation D, (1/3)·x - 2, which gives the values on Table E and Property A

The y-intercept of (1/3)·x - 2 = (0, -2), and the x-intercept = (6, 0)

Graph E corresponds to equation E, x³ = y, which gives the values on Table D  Property C, y is x cubed

6 0
3 years ago
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