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inysia [295]
3 years ago
12

Matching Functions

Mathematics
1 answer:
Ainat [17]3 years ago
6 0

Answer:

Graph A → Equation A → Table B → Property D

Graph D → Equation B → Table A → Property B

Graph B → Equation C → Table C → Property E

Graph C → Equation D → Table E → Property A

Graph E → Equation E → Table D → Property C

Step-by-step explanation:

Graph A corresponds to equation A, x·y = 2, and Table B → Property D

xy = 2 has a vertical asymptote at x = 0, and a horizontal asymptote at y = 0

y = 2/x, when x = 0, y = ∞

Graph D corresponds to equation B, -\left |  x\right | + 1 which corresponds to table A → Property B

The domain extends from (-∞, ∞), and [1, -∞)

Graph B corresponds to equation C, -(x + 2)² which gives the values in Table C and Property E wich is a horizontal shift of 2 units left and a reflection across the x-axis

Graph C corresponds to equation D, (1/3)·x - 2, which gives the values on Table E and Property A

The y-intercept of (1/3)·x - 2 = (0, -2), and the x-intercept = (6, 0)

Graph E corresponds to equation E, x³ = y, which gives the values on Table D  Property C, y is x cubed

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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