There is no way to factor this so i would assume the answer is no solution.
Answer:
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 m/sec, while the cat can run at a speed of 24 m/sec. How soon will they meet if they simultaneously start running towards each other?
Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.
Dog: Distance =Speed x time: x=30t
Cat: Distance = 200-x=24t
The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs
So they will meet after 3.7 seconds
To check: Distance travelled by dog:x=30(3.7)=111.11 meters
Distance travelled by cat: 24t=24(3.7)=88.89 meters
Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89=200 meters
Answer:
60
Step-by-step explanation:
Answer:
14 miles
Step-by-step explanation:
His goal is to reach 25 miles each week. The question tells us that he has run 5 on Monday and 6 on Tuesday. This amounts to 11 so far. This means he still had 14 miles to run to reach his goal of 25 miles.
Step-by-step explanation:
5n-2
5(4) - 2
20-2=18
A= 18
5n - 2 =48
5n=48+2
5n=50
divide by 5
n= 10
B=10