Let 
. The gradient of 
at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.
So the tangent plane has equation
Compute the gradient:
Evaluate the gradient at the given point:
Then the equation of the tangent plane is
Answer:
6.32
Step-by-step explanation:
Also known as 2√10
After we solve that we get 6.32455532
we then focus on these numbers here
6.3<em>24</em>55532
It doesnt round up stays the same so we get 6.32 to nearest hundredth
Answer:
C. 10 out of 20 is 5% is Not true
