Question

I need help!

Answer 1

Here is the solution...

1) $\sqrt[3]{135}$

Solution

We can rewrite $\sqrt[3]{135} = \sqrt[3]{27} *\sqrt[3]{5}$

Here, $\sqrt[3]{27} = 3$

Now substitute the value, we get

$\sqrt[3]{135} = 3 \sqrt[3]{5}$

The answer is $3\sqrt[3]{5}$

2) $-5\sqrt[3]{40} Solution[tex]-5\sqrt[3]{40} = -5\sqrt[3]{8} *\sqrt[3]{5}$

Here $\sqrt[3]{8} = \sqrt[3]{2^{3} } = 2$

Therefore, we get $-5*2\sqrt[3]{5} = -10 \sqrt[3]{5}$

The answer is-10 \sqrt[3]{5}[/tex]

2) $2\sqrt[3]{5} * 4\sqrt[3]{8}$

Solution

$\sqrt[3]{8} = 2$

Now plug in the above in the given expression, we get

$2\sqrt[3]{5} * 4*2 = 16\sqrt[3]{5}$                         {2*4*2 = 16]

The answer is $16\sqrt[3]{5}$