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zmey [24]
3 years ago
13

A motorboat traveling with the current went 80 miles in 4 hours. Against the current, it took 5 hours to travel the same distanc

e. Find the rate of the motorboat in calm water.
Mathematics
1 answer:
AysviL [449]3 years ago
3 0

Let x be the speed of the motorboat and y be the speed of the current.

Then, for downstream, the speed is x + y.

Now, speed = distance/time.

Distance = 80 miles.

Time for downstream = 4 hours.

So, x + y = 80/4 = 20     (1)

Against the current, that is for upstream, the speed is x - y.

Time for upstream = 5 hours.

x - y = 80/5 = 16     (2)

Adding (1) and (2), we get,

2x = 36

x = 18

Hence, rate of the motorboat in calm water = 18 miles/hour.

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*brainliest for best answer thank you* Solve for b.
vekshin1

Hello from MrBillDoesMath!

Answer:

The fourth choice,  b = +\- sqrt( sg + a^2)

Discussion:

s = (b^2 - a^2)/g     =>              multiply both sides by "g"

sg = b^2 - a^2        =>               add a^2 to both sides

sg + a^2 = b^2       =>                take the square root of each side

b = +\- sqrt( sg + a^2)


which is the fourth choice.


Thank you,

MrB

7 0
3 years ago
These cylinders are similar. Find the volume of
Basile [38]

Answer:

V_s=85\ cm^3

Step-by-step explanation:

Let V_s\ and\ V_b be the volumes of the smaller and bigger cylinder.

The formula for the volume of a cylinder is given by :

V=\pi r^2 h

As the two triangles are similar, the cube of their ratio would equal the ratio of their volume i.e.

\dfrac{V_s}{V_b}=(\dfrac{h_s}{h_b})^3\\\\\dfrac{V_s}{V_b}=(\dfrac{3}{5})^3\\\\\dfrac{V_s}{V_b}=0.216\\\\V_s=393\times 0.216\\\\V_s=84.8\\\\or\\\\V=85\ cm^3

So, the volume of the smaller cylinder is equal to 85\ cm^3.

3 0
3 years ago
What is the following product? Sqr5x^8y^2 sqr10x^3 sqr12y
PSYCHO15rus [73]

Step-by-step explanation:

\sqrt{5 {x}^{8} {y}^{2}  }  \times  \sqrt{10 {x}^{3} } \times  \sqrt{12y}   \\  \\  =   {x}^{4} y \sqrt{5}  \times x \sqrt{10x}  \times 2 \sqrt{3y}  \\  \\  = 2 {x}^{5} y \sqrt{5 \times 10x \times 3y}  \\  \\  =  2 {x}^{5} y \sqrt{5 \times 5 \times 2x \times 3y}  \\  \\ =  2 {x}^{5} y  \times 5\sqrt{ 2x \times 3y}   \\  \\  = 10 {x}^{5} y \sqrt{6xy}  \\

4 0
4 years ago
Which of the following show an element of the sample space for flipping 2 coins? (H= Heads, T= Tails) Check all that apply
Leni [432]

Answer:

All options

Step-by-step explanation:

If two coins are flipped, there are following possibilities

1. Both coins show heads

2. First coin shows heads and second shows tails

3. First coin shows tails and second shows heads

4. Both coins show tails

Let H denote heads and T denote tails

Then the sample space can be translated from the above events as:

Sample  Space for Flipping Two Coins = {HH, HT, TH, TT}

which means that all the options are correct ..

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3 years ago
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