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3 years ago

Simplify the sum. (7u^3 + 8u^2 + 7) + (8u^3 – 3u + 7)

Mathematics

2 answers:

Maslowich3 years ago

6 0

Answer:

15u^3 + 8u^2 - 6u + 13

Step-by-step explanation:

(7u^3 + 8u^2 + 8) + (8u^3 - 6u + 5)

= 7u^3 + 8u^2 + 8 + 8u^3 - 6u + 5

= 7u^3 + 8u^3 + 8u^2 - 6u + 5 + 8

*Now add the like terms

= 15u^3 + 8u^2 - 6u + 13

And that is all your can do!

mihalych1998 [28]3 years ago

3 0

15u^3 +8u^2 - 3u + 14

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Plzzz i need an actual answer plz

natta225 [31]

Answer:

185.60944

Step-by-step explanation:

Using the formulas

A=πrl+πr2

l=r2+h2

Solving forA

A=πr(r+h2+r2)=π·4·(4+102+42)≈185.60944

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3 years ago

What is the sum of 2n-3+2.15n+5.98

faust18 [17]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),

drek231 [11]

Answer:

Step-by-step explanation:

Step one

given the coordinates

ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)

AB=(-2,-2),(-1,3)

BC=(-1,3), (5, 3)

CD=(5, 3),(4, -2)

DA=(4, -2),(-2,-2)

The distance between points AB=

$AB= \sqrt (x_2-x_1)^2+(y_2-y_1)^2$

$AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1$

The distance between points BC=

$BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6$

The distance between points CD

$CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1$

The distance between points DA

$DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6$

Hence the perimeter = 5.1+6+5.1+6

= 22.2

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3 years ago

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babymother [125]

The first one is 6÷12×24

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3 years ago

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Makovka662 [10]

The first one is the answer you're looking for

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3 years ago