Answer:
need to know more
Step-by-step explanation:
Some definitions:
Sum - the result of adding values together
Term - a single number or variable (includes variables multiplied by numbers)
Factor - a number or variable that divides another number or expression evenly
Quotient - the result of dividing values by one another
Coefficient - a numerical or constant value often in front of a variable
In your equation:
Sum - (5x + 1)
5x and 1 are being added together, although we do not know the sum exactly, we know that the sum is equal to the value of 5 times x plus 1.
Term - (5x, 1, 3y)
All terms given above are applicable.
Factor - (9)
9 has been taken out of the expression that it is now being multiplied, which shows that it was factored out of that expression
Quotient - (9(5x + 1) / 3y)
The value of 9(5x + 1) is being divided by 3y. Though we do not know the quotient exactly, we know that the quotient is equal to the values given.
Coefficient - (5, 3)
Both 5 and 3 are numbers in front of variables.
Hope this helps!! :)
Answer:
A) P = 240
B) P + Po = 1040
C) P = 270.58
D) P+Po = 1070.58
E) Option B (compound interest) is better, as it generates more interest for the same inicial value, rate of interest and time
Step-by-step explanation:
The formula for simple interest is:
P = Po*r*t
Where P is the interest earned, Po is the inicial value, r is the rate of interest and t is the time.
The formula for compound interest is:
P+Po = Po*(1+r)^t
So we have that:
A) P = 800*0.06*5 = 240
B) P + Po = 800 + 240 = 1040
C) P+Po = 800*(1+0.06)^5 = 1070.58 -> P = 1070.58 - 800 = 270.58
D) P+Po = 1070.58
E) Option B (compound interest) is better, as it generates more interest for the same inicial value, rate of interest and time
Answer: D
Step-by-step explanation:

Let's take one of the equations and solve for a variable to use the substitution method.

Now replace this in the first equation.

Separate the terms.

Solve 20/5

Subtract 4 from both sides to isolate y.


Solve the difference.



Multiply by the reciprocal or the inverted fraction that is next to y to isolate it.


Now, in order to find x, replace y in any of the two equations.

Eh that ones hard you sure thats all the ansers