The value of the algebraic expressions when x = 5 are:
a) x² = <em>25</em>
<em>b) </em>(x + 3)² = <em>64</em>
We are given that x = 5.
<em>Required:</em>
Find the value of a.) x² and b.) (x + 3)²
To find the value of each algebraic expression when x = 5, substitute the value of x.
<em>Thus:</em>
a.) x²
x² = (5)²
x² = <em>25</em>
<em />
b.) (x + 3)²
(x + 3)² = (5 + 3)²
(x + 3)² = (8)²
(x + 3)² = <em>64</em>
Therefore, the value of the algebraic expressions when x = 5 are:
a) x² = <em>25</em>
<em>b) </em>(x + 3)² = <em>64</em>
Learn more about algebraic expressions on:
brainly.com/question/90420
9 students ride the bus. hope this helps!
Dnndhdhdhjshshshsnb
Since u done it on mine :) djhshdhd
I believe that it's 4 1/4
Because l•w= area, area= 320, l=w+4
width • (width +4)= 320
Distribute the multiplication over addition and move all to the left side.
w^2 +4w-320=0
(w-16)•(w+20)=0 yet, The product of two things is 0 if one is 0 or both are 0 so
w-16=0 so w=16 and
w+20=0 so w= -20
Now the width or length could not be negative so we discard the solution w=-20.
Answer
width= 16 inches
length =16+4=20
Verify
w•l=320
16•20=320✔️