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kumpel [21]
3 years ago
6

Factor completely x2 + 8x - 20

Mathematics
2 answers:
Oliga [24]3 years ago
8 0
Answer=(x-2) (x+10)

For this it helps if you do a factoring table but since I will not for the sake of not having an image to show you, I will try and explain my answer.

The expression is: 

x²+8x-20

In this case, since the x² doesn't have a number before it, we know that the beginning x's are solo, so we have...


(x+?)(x+?)

Now to solve the rest of the expression, we need to find two numbers that when multiplied equal -20 and when added equal 8.

a*b=-20
a+b=8

Lets look at the factor pairs of -20

(-1,20) or (1,-20) or (-2,10) or (2,-10) or (-4,5) or (4,-5)

Of all of these, only one pair have a sum of 8

So we can solve the expression

x²+8x-20=(x-2)(x+10)

kvv77 [185]3 years ago
3 0
X-2
Hope this helps!
Vote me brainliest!
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Answer:

The time duration of the two pipes restricted flow before the flow became normal is 4.5 minutes

Step-by-step explanation:

The given information are;

The time duration for the volume, V, of the basin to be filled by one of the pipe, A, = 12 minutes

The time duration for the volume, V, of the basin to be filled by the other pipe, B, = 16 minutes

Therefore, the flow rate of pipe A = V/12

The flow rate of pipe B = V/16

Due to the restriction, we have;

The proportion of its carrying capacity the first pipe, A, carries = 7/8 of the carrying capacity

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Whereby the tank is filled 3 minutes after the restriction is removed, we have;

\dfrac{7}{8} \times \dfrac{V}{12} \times t + \dfrac{5}{6} \times \dfrac{V}{16} \times t +  \dfrac{V}{12} \times 3 + \dfrac{V}{16} \times 3 = V

Simplifying gives;

\dfrac{(2\cdot t +7) \cdot V}{16}  = V

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If you want it in <em>Standard</em><em> </em><em>Form</em>:

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