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AnnZ [28]
3 years ago
11

In which quadrant does an angle of 1300° terminate? Assume the vertex of the angle is at the origin and one leg of the angle is

on the positive c-axis.
Find the quadrant of the other leg of the angle.
Mathematics
1 answer:
NikAS [45]3 years ago
6 0
<h3>Answer: quadrant 3</h3>

Work Shown:

Divide 1300 over 360

1300/360 = 3.611 approximately

Focus on the whole part 3. There are 3 full revolutions

3*360 = 1080, which subtracts off to get 1300-1080 = 220 left over.

The remainder 220 tells us where the angle points. It's in quadrant 3 since 220 degrees is between 180 degrees and 270 degrees.

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Multiply. Express in simplest form. 3/8 x 1/2
CaHeK987 [17]

Answer:

the answer is 3/16.

Step-by-step explanation:

First, let's take a look at the expression itself.

We have to multiply 3/8 and 1/2, which gives us the expression of

3/8*1/2

then, we multiply the numerator by the numerator and get 3, then we multiply the denominator by the other denominator which gets us 16. We put the two parts together and get

3/16

which is not simplifiable. So 3/16 is the simplest answer we can get.

5 0
2 years ago
4 - 3d = d - 8<br> solve for d
torisob [31]
Well you subtract d from both sides with would make 2D-4=-8. Then you subtract four to both sides which is -12. Then you divide -12 by 2D which is 6. D=-6
8 0
3 years ago
What is ? |6| + |5| =
777dan777 [17]

Answer:11

It is 11 because the lines beside the numbers represent ABSOLUTE VALUE. Absolute value basically means that wether or not it is a positive or negative number it will always be positive. Simplify-6+5=11

7 0
3 years ago
Simplify the expression 4x3 2x3
Fittoniya [83]

Answer:

onc

Step-by-step explanation:

3 0
2 years ago
Of those women who are diagnosed to have early-stage breast cancer, one-third eventually die of the disease. Suppose a screening
Finger [1]

Answer:

A) Alternative hypothesis; Ha: p_o > ⅔

B) Null hypothesis;

H0: p_o = ⅔

C) There is sufficient evidence to support the claim that the community screening programme was effective

D) p-value = 0

Its less than the significance value and so we will reject the null hypothesis and conclude that the community screening programme was effective

Step-by-step explanation:

A) We are told that ⅓ of those diagnosed eventually die of the disease. Thus, ⅔ is the fraction that will survive the disease.

Thus, the null hypothesis is;

H0: p_o = ⅔

We are told that a screening programme was started to increase the survival rate. Thus,the alternative hypothesis is;

Ha: p_o > ⅔

B) null hypothesis is;

H0: p_o = ⅔

C) 164 out of the 200 women selected survived the disease.

Thus sample proportion is;

p^ = 164/200

p^ = 0.82

For the z-score value, we will use the formula;

z = (p^ - p_o)/√((p_o(1 - p_o)/n)

Now, p_o = ⅔ = 0.67

Thus;

z = (0.82 - 0.67)/√((0.67(1 - 0.67)/200)

z = 4.51

From online p-value from z-score calculator, we have p-value ≈ 0

This is less than the significant level of 0.05 and therefore we will reject the null hypothesis and conclude that the community screening program was effective.

D) p-value ≈ 0

Reject the null hypothesis

4 0
2 years ago
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