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3 years ago

Write 0.735353535 as a decimal

Mathematics

1 answer:

mario62 [17]3 years ago

4 0

0.735353535 is already a decimal.

Example:

To get the decimal you have to divide the numerator by the denominator of a fraction to get the decimal and 0.735353535 isn't a fraction.

Answer:

0.735353535

You might be interested in

Select the correct answer.<br> Which statement is true?

dusya [7]

Answer:

third option is the correct

Step-by-step explanation:

A function is "odd" when f (-x) = - f (x) for all x. ... For example, functions like

f (x) = x3,
f (x) = x5,
f (x) = x7, ... are odd functions.

6 0

2 years ago

Read 2 more answers

A side of the triangle below has been extended to form an exterior angle of 164". Find

Arada [10]

Given:

Measure of exterior angle = 164°

The measure of opposite interior angles are x° and 53°.

To find:

The value of x.

Solution:

According to the Exterior Angle Theorem, in a triangle the measure of an exterior angles is always equal to the sum of measures of two opposite interior angles.

Using Exterior Angle Theorem, we get

$x^\circ+53^\circ=164^\circ$

$x^\circ=164^\circ-53^\circ$

$x^\circ=111^\circ$

$x=111$

Therefore, the value of x is 111.

3 0

3 years ago

Please show your work <br> simplify the expression (-5-c)(-1)

frozen [14]

(-5-c)(-1)
can write as (-1)(-5-c)
multiply(-1) to (-5) then multiply (-1) to(-5)
answer 5+c

4 0

3 years ago

Read 2 more answers

. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an

Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12$

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when $X = 59.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{59.5 - 56}{1.12}$

$Z = 3.1$

$Z = 3.1$ has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0

3 years ago

A can of soda can have a minimum of 35 milligrams of sodium and a maximum of 45 milligrams of sodium. Write an absolute value in

inessss [21]

An absolute value inequality that represents the acceptable amounts of sodium is; 35 ≤ A ≤ 45

<h3>What is the Absolute Value Inequality?</h3>

We are told that a can of soda can have a minimum of 35 milligrams of sodium and a maximum of 45 milligrams of sodium.

Now, an absolute value inequality that represents this expression would be written as;

35 ≤ A ≤ 45

Thus, we conclude that an absolute value inequality that represents the acceptable amounts of sodium is; 35 ≤ A ≤ 45

Read more about Absolute Value Inequality at; brainly.com/question/13282457

#SPJ1

8 0

2 years ago