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ycow [4]
3 years ago
7

The diameter of a circular chip is doubled to use in a new board game. The area of the new chip will be

Mathematics
2 answers:
nikitadnepr [17]3 years ago
7 0

Answer: A_2=\frac{\pi(2D)^{2}}{4}


Step-by-step explanation:

1. You have the following formula for calculate the area of the original circular chip:

A_1=\frac{\pi(D)^{2}}{4}

Where D is the diameter of the circle.

2. Then, if the diameter of the original circular chip is doubled (2D) to use in a new board game, the area of the new chip can be calculated with the following formula:

A_2=\frac{\pi(2D)^{2}}{4}


iVinArrow [24]3 years ago
5 0

Answer:

The area of the new chip will be 4 times the area of old chip

Step-by-step explanation:

<u>Formula</u>

Area of circle = πr²  where r is the radius if circle

Let d  be the diameter of old circular chip

radius r = d/2

<u>To find the area of old chip</u>

Area = πr² = π(d/2)²

Area = πd²/4

<u>To find the area of new chip</u>

Here diameter = 2d

radius  r = 2d/2 = d

Area = πr² = πd²

Therefore the area of the new chip will be 4 times the area of old chip


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Read 2 more answers
The U.S. and many other countries have recently tightened airport security. A sociologist is interested in estimating the propor
melisa1 [442]

Answer:

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: H_{0}: p = 0.7

And the alternate hypothesis is: H_{a}: p > 0.7

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7, \sigma = \sqrt{0.7*0.3}

The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

This means that n = 500, X = \frac{375}{500} = 0.75

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z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.75 - 0.7}{\frac{\sqrt{0.7*0.3}}{\sqrt{350}}}

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P-value of the test:

Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

Z = 2.44 has a pvalue of 0.9927

1 - 0.9927 = 0.0073

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

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