Answer:
m∠P = 82°
m∠Q = 49°
m∠R = 49°
Step-by-step explanation:
<em>In the isosceles triangle, the base angles are equal in measures</em>
In Δ PQR
∵ PQ = PR
∴ Δ PQR is an isosceles triangle
∵ ∠Q and ∠R are the base angles
→ By using the fact above
∴ m∠Q = m∠R
∵ m∠Q = (3x + 25)°
∵ m∠R = (2x + 33)°
→ Equate them
∴ 3x + 25 = 2x + 33
→ Subtract 2x from both sides
∵ 3x - 2x + 25 = 2x - 2x + 33
∴ x + 25 = 33
→ Subtract 25 from both sides
∵ x + 25 - 25 = 33 - 25
∴ x = 8
→ Substitute the value of x in the measures of angles Q and R
∵ m∠Q = 3(8) + 25 = 24 + 25
∴ m∠Q = 49°
∵ m∠R = 2(8) + 33 = 16 + 33
∴ m∠R = 49°
∵ The sum of the measures of the interior angles of a Δ is 180°
∴ m∠P + m∠Q + m∠R = 180°
→ Substitute the measures of angles Q and R
∵ m∠P + 49 + 49 = 180
∴ m∠P + 98 = 180
→ Subtract 98 from both sides
∵ m∠P + 98 - 98 = 180 - 98
∴ m∠P = 82°
Answer:
x= 
Step-by-step explanation:
Answer:
35 ok
Step-by-step explanation:
35 Men ok byeee3eeeeeeeeeeeeewwww
Answer:
37.8metres
Step-by-step explanation:
The arc of the arrow can be modeled by the equation:
y=-0.02x²+0.65x+4
Where x is the horizontal distance (in meters) from Linda and y is the height (in meters) of the arrow.
The arrow hits the ground when its height (y) is zero.
Therefore, we determine the value(s) of x for which:
y=-0.02x²+0.65x+4=0
Using a calculator to solve the quadratic equation:
x=37.79 or -5.29
Since the distance cannot be a negative value, we ignore -5.29.
The distance from Linda when the arrow hits the ground is 37.8metres (to the nearest tenth)
