Answer:
m∠P = 82°
m∠Q = 49°
m∠R = 49°
Step-by-step explanation:
<em>In the isosceles triangle, the base angles are equal in measures</em>
In Δ PQR
∵ PQ = PR
∴ Δ PQR is an isosceles triangle
∵ ∠Q and ∠R are the base angles
→ By using the fact above
∴ m∠Q = m∠R
∵ m∠Q = (3x + 25)°
∵ m∠R = (2x + 33)°
→ Equate them
∴ 3x + 25 = 2x + 33
→ Subtract 2x from both sides
∵ 3x - 2x + 25 = 2x - 2x + 33
∴ x + 25 = 33
→ Subtract 25 from both sides
∵ x + 25 - 25 = 33 - 25
∴ x = 8
→ Substitute the value of x in the measures of angles Q and R
∵ m∠Q = 3(8) + 25 = 24 + 25
∴ m∠Q = 49°
∵ m∠R = 2(8) + 33 = 16 + 33
∴ m∠R = 49°
∵ The sum of the measures of the interior angles of a Δ is 180°
∴ m∠P + m∠Q + m∠R = 180°
→ Substitute the measures of angles Q and R
∵ m∠P + 49 + 49 = 180
∴ m∠P + 98 = 180
→ Subtract 98 from both sides
∵ m∠P + 98 - 98 = 180 - 98
∴ m∠P = 82°
