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3 years ago

Which ratio correctly compares 60 mm to 45 cm?

1 answer:

6 0

First we need to convert cm to mm
45 cm = 450 mm

Now our ratio looks like this
60/450
We can divide both by 30 and once we do that our ratio will look like this:
2/15

That means the answer is B

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How do I solve 80+(-22 4/15)

alukav5142 [94]

80 -224
——
15

976
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15

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7 0

3 years ago

PLEASE HELP ME I WILL GIVE BRAINLIEST

crimeas [40]

Answer:

Step-by-step explanation:

can u plz write it

7 0

3 years ago

The indicated function y1(x) is a solution of the given differential equation. use reduction of order or formula (5) in section

Ber [7]

Given that $y_1=e^{2x/3}$ , we can use reduction of order to find a solution $y_2=v(x)y_1=ve^{2x/3}$ .

$\implies {y_2}'=\dfrac23ve^{2x/3}+v'e^{2x/3}=\left(\dfrac23v+v'\right)e^{2x/3}$
$\implies{y_2}''=\dfrac23\left(\dfrac23v+v'\right)e^{2x/3}+v''e^{2x/3}=\left(\dfrac49v+v'+v''\right)e^{2x/3}$

$\implies9y''-12y'+4y=0$
$\implies 9\left(\dfrac49v+v'+v''\right)e^{2x/3}-12\left(\dfrac23v+v'\right)e^{2x/3}+4ve^{2x/3}=0$
$\implies9v''-3v'=0$

Let $u=v'$ , so that

$9u'-3u=0\implies 3u'-u=0\implies u'-\dfrac13u=0$
$e^{-x/3}u'-\dfrac13e^{-x/3}u=0$
$\left(e^{-x/3}u\right)'=0$
$e^{-x/3}u=C_1$
$u=C_1e^{x/3}$

$\implies v'=C_1e^{x/3}$
$\implies v=3C_1e^{x/3}+C_2$

$\implies y_2=\left(3C_1e^{x/3}+C_2\right)e^{2x/3}$
$\implies y_2=3C_1e^x+C_2e^{2x/3}$

Since $y_1$ already accounts for the $e^{2x/3}$ term, we end up with

$y_2=e^x$

as the remaining fundamental solution to the ODE.

7 0

3 years ago

Simplify to a + bi form. (6-2i)^2

Zigmanuir [339]

The answer is 32-24i
hope it helps
please mark as brainliest

5 0

3 years ago

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

ANTONII [103]

Answer:

the answer is (3,4)

Step-by-step explanation:

because if you check wich quadrant it is in and you check the number you can see which one it is. x,y that is how it goes so 3,4 should be correct if you line them up.

6 0

2 years ago