All categories

2 years ago

A square pyramid with a height of 7 inches has volume of 47.25 cubic inches. Find the side length of the square base

1 answer:

7 0

Hello,
Volume of the square pyramid=
1/3×B×h where B represent Base and h represent height

Now, substitute the information that we had from this problem into the formula.
47.25=1/3×B×7
Times 3 from both side
141.75=7B
Divide B from both side
B=20.25 square inches
B=s^2
Square root it to get
s=4.5 inches. As a result, the side length of square base is 4.5 inches. Hope it help!

You might be interested in

42 of the 50 coffee mugs at Nicole's Pancake House are dirty. What percentage of the

LenKa [72]

Answer:

84%

Step-by-step explanation:

of the means division.

42/50 = 84/100 = 84%

5 0

1 year ago

Read 2 more answers

2,3 coordinates plot it.

zhenek [66]

It should look like this

8 0

2 years ago

If Walgreens sells 4 candy bars for $2.00, what is the cost of 1 candy bar?

SVEN [57.7K]

Answer: 50 cents

Step-by-step explanation:

$2.00÷4= 0.50

each candy bar is 50 cents.

maybe give a little more effort next time because this was a very simple question :)

8 0

3 years ago

A rectangular garden must have a perimeter of 160 feet and an area of at least 1300 square feet. Describe the possible lengths o

Morgarella [4.7K]

Answer: The lengths of the garden are 57.32 feet and 22.68 feet (approximately)

Step-by-step explanation: The area has been given as 1300 which means,

Area = L x W

1300 = L x W ———(1)

Also the perimeter has been given as 160, hence we also have

Perimeter = 2(L + W)

160 = 2(L + W)

80 = L + W ———(2)

From equation (2), make L the subject of the equation

L = 80 - W

Substitute for the value of L into equation (1)

1300 = L x W

1300 = (80 - W) x W

1300 = 80W - W^2

Rearranging the equation we now have;

W^2 - 80W + 1300 = 0

Since we cannot factorize we shall apply the quadratic equation formula to solve for W. Please refer to the attachment for details of this.

Having calculated the value of W to be either 57.32 or 22.68, we can now find the value of L as follows;

Substitute for the value of W into equation (1)

1300 = L x W

1300 = L x 57.32

Divide both sides of the equation by 57.32

22.68 = L.

(Note that if we take the other value of W which is 22.68, the value of L shall be 57.32)

Since the area of the rectangular garden must be AT LEAST 1300 square feet we shall use the exact values for;

Length = 57.32 feet

Width = 22.68 feet

3 0

3 years ago

Read 2 more answers

State whether each sequence is arithmetic and justify your answer. If the sequence is arithmetic, write a recursive and an expli

nasty-shy [4]

Answer:

Part A

$f(n)=52-12(n-1)$

$f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.$

Part B

$(2,4,8,16,32)\: \:$ Geometric Sequence

Part C

1/4,3/4,5/4,7/4,9/4

$g(n)=\frac{1}{4}+\frac{2}{4}(n-1)\\f(n)=\left\{\begin{matrix}1/4if \: \:n=1 & \\ f(n+1)+2/4& if\: n\geq 2 \end{matrix}\right$

Part D:

$h(n)=1.1+0.4(n-1)\\h(n)=\left\{\begin{matrix}1.1 & if\:n=1 \\ h(n+1)+0.4 & if\:n\geq 2\end{matrix}\right$

Step-by-step explanation:

By definition, an Arithmetic Sequence holds the same difference between each following number.

Part A

$(52,40, 28, 16)\\52-40=12\\40-28=12\\28-16=12\\d=12$

Explicit Formula

To write an explicit formula is to write it as function.

$f(n)=52-12(n-1)$

Recursive Formula

To write it as recursive formula, is to write it as recurrence given to some restrictions:

$f(n)=\left\{\begin{matrix}52\: \:if \: \:n=1 & \\f(n+1)+12& if\: n\geq 2 \end{matrix}\right.$

Part B

$(2,4,8,16,32)\: \:$

Geometric Sequence, since 2*2=4 8*2=16 and 16*2=32 and 8+2=10 8+16=24

Part C

$(\frac{1}{4},\frac{3}{4},\frac{5}{4},\frac{7}{4},\frac{9}{4})\\\$

Arithmetic Sequence, difference

$d=\frac{2}{4}$

Explicit Formula:

$g(n)=\frac{1}{4}+\frac{2}{4}(n-1)$

Recursive Formula

$g(n)=\left\{\begin{matrix}\frac{1}{4} &if\:n=1 \\ g(n+1)+\frac{2}{4} &if\: n\geq 2\end{matrix}\right.$

Part D

(1.1,1.5,1.9,2.3,2.7) Arithmetic Sequence, difference d=0.4

Explicit formula

$h(n)=1.1+0.4(n-1)\\$

Recursive Formula

$h(n)=\left\{\begin{matrix}1.1 &if\:n=1 \\ h(n+1)+0.4 &if\: n\geq 2\end{matrix}\right.$

6 0

3 years ago