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2 years ago

10) Choose the quadrilateral with 4 sides, opposite sides parallel, and no right

Mathematics

1 answer:

sergey [27]2 years ago

6 0

B it would be enough to obtuse shape

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- 2a = - 20<br> What is the most simplest answer?

Evgesh-ka [11]

- 2a = - 20 | x (-)

2a = 20

a = 20 : 2

a = 10

6 0

3 years ago

Read 2 more answers

Determine the length of PN and the value of y

e-lub [12.9K]

Answer:

Side PN=26

y=16

Step-by-step explanation:

I put a photo of my work. It’s easier to do that then to try and put it all in words

7 0

3 years ago

Line g passes through points (5, 9) and (3, 2). Line h passes through points (9, 10) and (2, 12). Are line g and line h parallel

icang [17]

For this case we find the slopes of each of the lines:

The g line passes through the following points:

$(x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)$

So, the slope is:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}$

Line h passes through the following points:

$(x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)$

So, the slope is:

$m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}$

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.

It is observed that lines g and h are not parallel. We verify if they are perpendicular:

$\frac {7} {2} * - \frac {2} {7} = \frac {-14} {14} = - 1$

Thus, the lines are perpendicular.

Answer:

The lines are perpendicular.

8 0

3 years ago

Miguel is making trail mix. He uses 5 1/3 ounces of nuts and 2 3/4 ounces of raisins. Which

Lady_Fox [76]

It doesn’t show which options?
But the difference would be 2 7/12 or 2.58

4 0

2 years ago

If numerator is 2 less than the denominator of a rational number and when 1 is subtracted from numerator and denominator both, t

xenn [34]

Answer:

$\frac{3}{5}$

Step-by-step explanation:

Let the denominator be x
So, numerator = x - 2
According to the given condition: when 1 is subtracted from numerator and denominator both, the resulting new rational number in its simplest form is $\frac{1}{2}$

$\implies \frac{x-2-1}{x-1}=\frac{1}{2}$

$\implies \frac{x-3}{x-1}=\frac{1}{2}$

$\implies 2(x-3)=x -1$

$\implies 2x-6=x -1$

$\implies 2x-x=6-1$

$\implies x=5$

$\implies x-2=-5-2= 3$

$Required \: rational\: number = \frac{3}{5}$

6 0

2 years ago