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san4es73 [151]
3 years ago
8

Apply the laws of probability and calculate the probability the offspring of the cousin marriage of 3 x 7 will have the trait. (

enter a decimal fraction between 0.00 and 1.00)

Mathematics
1 answer:
lilavasa [31]3 years ago
6 0

Answer:

0.16

Step-by-step explanation:

The calculation of probability by applying the is shown below:-

It is evident from the pedigree that the mode of inheritance is recessive and the characteristic is recessive that's also phenotype of disease is only seen if the genotype is aa.

The genotype of 1. In pedigree Can be either AA or Aa.

The chance that the offspring of the 3\times 7 cousin marriage will have the characteristic is

= \frac{1}{6}

which gives results

= 0.16

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What is the quotient in simplified form ? Need help please
Gre4nikov [31]

Answer:

  -\dfrac{4a^{12}b^8}{5}

Step-by-step explanation:

The applicable rules of exponents are ...

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8 0
3 years ago
Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.
WINSTONCH [101]

Answer:

a) y(t) = y_{0}e^{4t} + 2. It does not have a steady state

b) y(t) = y_{0}e^{-4t} + 2. It has a steady state.

Step-by-step explanation:

a) y' -4y = -8

The first step is finding y_{n}(t). So:

y' - 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r - 4 = 0

r = 4

So:

y_{n}(t) = y_{0}e^{4t}

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' -4(y_{p}) = -8

(C)' - 4C = -8

C is a constant, so (C)' = 0.

-4C = -8

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{4t} + 2

b) y' +4y = 8

The first step is finding y_{n}(t). So:

y' + 4y = 0

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

r + 4 =

r = -4

So:

y_{n}(t) = y_{0}e^{-4t}

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

y_{p}(t) = C

So

(y_{p})' +4(y_{p}) = 8

(C)' + 4C = 8

C is a constant, so (C)' = 0.

4C = 8

C = 2

The solution in the form is

y(t) = y_{n}(t) + y_{p}(t)

y(t) = y_{0}e^{-4t} + 2

6 0
3 years ago
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