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NeX [460]
3 years ago
8

Plzz help will help you if i can!!!!! How does a house cat exhibit the seven characteristics of life?

Mathematics
2 answers:
Bezzdna [24]3 years ago
5 0

A house cat grows and reproduces just like us. They also have metabolism.

A house cat gets its traits from its genes. They also have cells and homeostasis like us. They also have senses.

Hope this helps

-AaronWiseIsBae

leonid [27]3 years ago
4 0

1) <u>Growth:</u> A housecat grows, just like any living creature

2) <u>Metabolism:</u> Like us human, housecats also have metabolism, which helps it maintain life

3) <u>Reproduction:</u> To continue to animal race of cats, they must be able to reproduce, or else they would go extinct

4) <u>Cellular Organization:</u> Each Cell must perform their duty, or else the cat would die

5) <u>Homeostasis:</u> Each cat must have an equilibrium, such as balance, balance of temperature of cat vs. the nature, etc.

6) <u>Heredity:</u> Each cat must inherit traits from it's ancestor that allows it to survive better in the earth

7) <u>Response to stimuli:</u> Each cat must be able to detect changes in the internal and external environment

hope this helps


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Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 10 minutes:

This means that m = 10, \mu = \frac{1}{10} = 0.1

A. What is the probability that the arrival time between customers will be 7 minutes or less?

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

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-1(3x^2+15x+x+5)

-1(3x^2+16x+5)

-3x^2-16x-5

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