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3 years ago

PLEASE HELP ME ASAP!! ITS MY LAST TEST ON EG!! 20 POINTS!

Mathematics

1 answer:

puteri [66]3 years ago

6 0

Answer:

V = 1/3 (90)(6) m³

Step-by-step explanation:

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Show that area under multivariate normal distribution over the whole range in unity. Find characteristics function of multivaria

kenny6666 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Math Help? 20 Points

Pachacha [2.7K]

V= LWH so 3.75cm^3 or 3 (3/4)

Multiply those three sides and it comes out to 3.75

5 0

3 years ago

(Please help!) Divide: (4x² +33x+37) = (x+7) Quotient: Remainder:

Drupady [299]

Answer:

Step-by-step explanation:

4x² + 33 x + 37 = (4 x + 5) × (x + 7) + 2

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3 years ago

Whoever helps me will be lucky for the rest of your life

Anvisha [2.4K]

Answer:

A) 3.5

16 shovels full

Step-by-step explanation:

9x + 13 = 17x - 15

8x = 28

x = 3.5

20 + 5x = 32 + 4.25x

0.75x = 12

x = 16

7 0

3 years ago

If X²⁰¹³ + 1/X²⁰¹³ = 2, then find the value of X²⁰²² + 1/X²⁰²² = ?

enyata [817]

Step-by-step explanation:

$\bf➤ \underline{Given-} \\$

$\sf{x^{2013} + \frac{1}{x^{2013}} = 2}\\$

$\bf➤ \underline{To\: find-} \\$

$\sf {the\: value \: of \: x^{2022} + \frac{1}{x^{2022}}= ?}\\$

$\bf ➤\underline{Solution-} \\$

Let us assume that:

$\rm: \longmapsto u = {x}^{2013}$

Therefore, the equation becomes:

$\rm: \longmapsto u + \dfrac{1}{u} = 2$

$\rm: \longmapsto \dfrac{ {u}^{2} + 1}{u} = 2$

$\rm: \longmapsto{u}^{2} + 1 = 2u$

$\rm: \longmapsto{u}^{2} - 2u + 1 =0$

$\rm: \longmapsto {(u - 1)}^{2} =0$

$\rm: \longmapsto u = 1$

Now substitute the value of u. We get:

$\rm: \longmapsto {x}^{2013} = 1$

$\rm: \longmapsto x = 1$

Therefore:

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 1 + 1$

$\rm: \longmapsto {x}^{2022} + \dfrac{1}{ {x}^{2022} } = 2$

★ Which is our required answer.

$\textsf{\large{\underline{More To Know}:}}$

(a + b)² = a² + 2ab + b²

(a - b)² = a² - 2ab + b²

a² - b² = (a + b)(a - b)

(a + b)³ = a³ + 3ab(a + b) + b³

(a - b)³ = a³ - 3ab(a - b) - b³

a³ + b³ = (a + b)(a² - ab + b²)

a³ - b³ = (a - b)(a² + ab + b²)

(x + a)(x + b) = x² + (a + b)x + ab

(x + a)(x - b) = x² + (a - b)x - ab

(x - a)(x + b) = x² - (a - b)x - ab

(x - a)(x - b) = x² - (a + b)x + ab

6 0

3 years ago