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Lady bird [3.3K]

3 years ago

15

‍♂️ somebody help please

1 answer:

Alex73 [517]3 years ago

3 0

1/4 y = 13
y = 13 x 4
y = 52

answer is C. 52

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Choose the equation that represents the line passing through the point (−2, −3) with a slope of −6.

Vladimir79 [104]

Y = -6x - 15
We’re already at -3 (y) and the slope is negative so the y intercept is < -3. X is -2 and we need to find the y when x is 0. -2 is 2 away from 0 and 6 (the slope) times 2 is 12. -3 - 12 = - 15

4 0

2 years ago

Dy/dx of ln(x/x^²+1)

exis [7]

$\dfrac{dy}{dx}\ \ln\left(\dfrac{x}{x^2+1}\right)=\dfrac{1}{\frac{x}{x^2+1}}\cdot\dfrac{x'(x^2+1)-x(x^2+1)'}{(x^2+1)^2}\\\\=\dfrac{x^2+1}{x}\cdot\dfrac{1(x^2+1)-x(2x)}{(x^2+1)^2}=\dfrac{1}{x}\cdot\dfrac{x^2+1-2x^2}{x^2+1}=\dfrac{1-x^2}{x^3+x}\\\\Used:\\\\(\ln(x))'=\dfrac{1}{x}\\\\\left[f(g(x))\right]'=f'(g(x))\cdot g'(x)\\\\\left(\dfrac{f(x)}{g(x)}\right)'=\dfrac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}$

5 0

3 years ago

What is 9 times 3 fourths ?

Elena L [17]

9 * 3/4 = 6.75

You could change 3/4 into a decimal by dividing 3 by 4, which equals ,75.

4 0

3 years ago

Helpppp pleasee

ICE Princess25 [194]

Using the recursion equation, it is found that the value of the 2nd iterate is:

$x_2 = 3.16228$

<h3>What is the recursive equation?</h3>

The value of the nth iteration is given by:

$x_n = \frac{x_{n-1} + \frac{10}{x_{n-1}}}{2}$

The initial estimate is:

$x_0 = 3.1$

Hence, the 1st iterate is given by:

$x_1 = \frac{x_0 + \frac{10}{x_0}}{2} = \frac{3.1 + \frac{10}{3.1}}{2} = 3.1629$

The 2nd iterate is:

$x_2 = \frac{x_1 + \frac{10}{x_1}}{2} = \frac{3.1629 + \frac{10}{3.1629}}{2} = 3.16228$

Thus, the fourth option is correct.

You can learn more about recursive equations at brainly.com/question/6561461

6 0

2 years ago

A mixture of compounds X and Y in a 0.100-cm cell had an absorbance of 0.215 at 272 nm and 0.191 at 327 nm. Find [X] and [Y] in

Oksi-84 [34.3K]

Answer: The concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

Step-by-step explanation:

Since we have given that

At 272 nm, absorbance = 0.215

At 327 nm, absorbance = 0.191

As we have given that

Compound X Compound Y

272 16400 3870

327 3990 6420

So, our equations becomes

$16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191$

By solving these two equations, we get that

$C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}$

Hence, the concentration of X is $7.13582\times 10^{-6}$ and the concentration of Y is $2.53159\times 10^{-5}$ .

5 0

3 years ago