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shtirl [24]
3 years ago
15

Please help me do this question

Mathematics
2 answers:
beks73 [17]3 years ago
7 0

Hey!

------------------------------------------------

Steps To Solve:

~Divide

500 / 140 = 3.5714...

~Round down since max limit is 500lb.

3.5714... = 3

------------------------------------------------

Answer:

\large\boxed{3~teenagers~can~ride!}

------------------------------------------------

Hope This Helped! Good Luck!

bija089 [108]3 years ago
4 0

Answer:

I would say three person(s).

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there was 5/8 of a pallet in the fridge. Danielle ate 1/4 of the leftover pie how much pie did he have left
yuradex [85]

Answer:

3/8

Step-by-step explanation:

1/4= 2/8

5/8-2/8=3/8

7 0
3 years ago
A customer buys a different book that has an original selling price of $38. The book is discounted 25%. The customer must pay a
krok68 [10]
$38.00 x 0.25= $9.50
$38.00 - $9.50= $28.75
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5 0
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Juanita can complete 12 math problems in 40 minutes. How many problems can she complete in 60 minutes
RSB [31]

Answer:

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Step-by-step explanation:

3 0
3 years ago
Determine whether f(x) = –5x^2 – 10x + 6 has a maximum or a minimum value.
Blizzard [7]

First,

We are dealing with parabola since the equation has a form of,

y=ax^2+bx+c

Here the vertex of an up - down facing parabola has a form of,

x_v=-\dfrac{b}{2a}

The parameters we have are,

a=-5,b=-10, c=6

Plug them in vertex formula,

x_v=-\dfrac{-10}{2(-5)}=-1

Plug in the x_v into the equation,

y_v=-5(-1)^2-10(-1)+6=11

We now got a point parabola vertex with coordinates,

(x_v, y_v)\Longrightarrow(-1,11)

From here we emerge two rules:

  • If a then vertex is max value
  • If a>0 then vertex is min value

So our vertex is minimum value since,

a=-5\Longleftrightarrow a

Hope this helps.

r3t40

7 0
3 years ago
Each day, I use 4 bags of milk for tea. In how much of a day wlll I use 1/2 of a bag of milk?
Slav-nsk [51]
1 day use 4 bags
? day use 1/2 bag

Cross multiply
(1•1/2)/4= 1/2•1/4= 1/8 of the day

In 1/8 of the day 1/2 of bag of milk will be used.
3 0
3 years ago
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