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seropon [69]
3 years ago
7

Jeremy has 3 pounds of ground beef to make hamburgers. How many 1/3-pound hamburgers can he make?

Mathematics
2 answers:
never [62]3 years ago
8 0

Answer:

the answer is 9

Step-by-step explanation:

3x1/3 you don't do nothing with the 1 so don't multply it then what you do is 3x3=9

Tpy6a [65]3 years ago
7 0

Answer:

He can make 9 hamburgers

Step-by-step explanation:

if he makes hamburgers that are 1/3 of a pound then when he makes 3 he uses a whole pound so when he makes 9 he uses all 3 pounds.

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Stella bought 14 purses for $50. The next day she bought 2 more for a total of $38. What was the mean cost per purse?
denpristay [2]

Answer:

$48.5

Step-by-step explanation:

Given data

Number of purses= 14+2= 16

Cost of 14 purses= $50

Cost of 2 purses= $38

Let us use the weighted cost method

Mean cost = (14*50+ 2*38)/16

Mean cost = (700+ 76)/16

Mean cost = 776/16

Mean cost =$48.5

8 0
3 years ago
How do you subtract 1 integer by another
nikdorinn [45]
Use absolute value. If both signs are negative you will get a negative number. if both are positive you get positive. if the signs are different, subtract the smaller absolute value from the larger absolute value.
8 0
3 years ago
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Find the slope of the line that passes through (4, 10) and (1, 2).
givi [52]
The slope is about 2.6667, the angle is almost 70° and the distance is 8.5 ish maybe even a little less
8 0
3 years ago
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Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne
Pavlova-9 [17]

Answer:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

p_v =P(t_{(15)}>1.507)=0.076

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

\bar X_{CTS}=2.35 represent the mean for the sample CTS

\bar X_{N}=1.83 represent the mean for the sample Normal

s_{CTS}=0.88 represent the sample standard deviation for the sample of CTS

s_{N}=0.54 represent the sample standard deviation for the sample of Normal

n_{CTS}=10 sample size selected for the CTS

n_{N}=7 sample size selected for the Normal

\alpha=0.01 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis:\mu_{CTS} \leq \mu_{N}

Alternative hypothesis:\mu_{CTS} > \mu_{N}

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{CTS}+n_{N}-2=10+7-2=15

Since is a one side right tailed test the p value would be:

p_v =P(t_{(15)}>1.507)=0.076

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

6 0
4 years ago
Hello, I need help. (Again TwT)
Effectus [21]
Yes the answer is 2/3
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3 years ago
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