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2 years ago

Find the measure of angle E.

Mathematics

1 answer:

9966 [12]2 years ago

4 0

Add all of the interior angles to 1260. Then you simplify for x. After that you plug in what you found for X in the E expression.

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Please helppp!! Find the missing side . Round to the nearest tenth

olga nikolaevna [1]

Answer:

7. 7.8

Step-by-step explanation:

We can use Tan of this angle to find the missing side (in this case, the side adjacent to the angle measuring 57°)

Tan A = (opposite side)/(adjacent side)

Tan 57° = 12/x

solve for x

x(Tan 57°) = 12

x = 12/(Tan 57°)

x = 7.8 (rounded to the nearest tenth)

6 0

2 years ago

Please help thank you !

Vikentia [17]

Answer:

x ≈ 14.57

Step-by-step explanation:

using the sine ratio in the right triangle

sin59° = $\frac{opposite}{hypotenuse}$ = $\frac{x}{17}$ ( multiply both sides by 17 )

17 × sin59° = x , then

x ≈ 14.57 ( to 2 dec. places )

8 0

2 years ago

3. Find the circumcenter of triangle ABC with A(1,6), B(1,4), C(5,4). (1point). a)(5,3). b)(3,5). c)(7.3). d)(1,7). 5.What is th

Harrizon [31]

For problem number 3, the answer is (3, 5). The correct answer between all the choices given is the second choice or letter B.

For problem number 5, the answer is median. The correct answer between all the choices given is the third choice or letter C.

I am hoping that these answers have satisfied your queries and it will be able to help you, and if you’d like, feel free to ask another question.

6 0

3 years ago

Read 2 more answers

I dont get the whole line graphing solution thing please help me out

SVEN [57.7K]

(3,-2) it’s where the both lines meet

7 0

2 years ago

Captain Jessica has a ship, the H.M.S. Khan. The ship is two furlongs from the dread pirate Luis and his merciless band of thiev

erik [133]

Answer: Probability that both the pirate and the Captain hit each other's ships is $\frac{1}{9}$

Step-by-step explanation:

since we have given that

Probability that the captain hits the pirate ship is given by

$\frac{4}{9}$

Probability that the pirate hits the Captains's ship is given by

$\frac{1}{4}$

So, we have to find the "Probability that both the pirate and the Captain hit each other's ship" is given by

$P(\text{Captain hits})\times P(\text{ Pirates hit})\\\\=\frac{4}{9}\times \frac{1}{4}\\\\=\frac{1}{9}$

Hence, probability that both the pirate and the Captain hit each other's ships is $\frac{1}{9}$

6 0

2 years ago