All categories

3 years ago

Very easy math 6x + 9 = 39 solve for x

Mathematics

2 answers:

pentagon [3]3 years ago

7 0

Answer:

Step-by-step explanation:

laiz [17]3 years ago

7 0

Answer:

x=5

Step-by-step explanation:

6x+9=39

-9 -9

6x/6=30/6

x=5

You might be interested in

Find the midpoint of the segment with the following endpoints.<br> (8,2) and (1,10)

ioda

Answer:

I am not sure but i think the midpoint is 4.5 and 6

5 0

3 years ago

Find the limit, if it exists. (If an answer does not exist, enter DNE.) lim (x, y) → (0, 0) x4 − 34y2 x2 + 17y2

HACTEHA [7]

Answer:

Step-by-step explanation:

Given the limit of the function $\lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}$ , to find the limit, the following steps must be taken.

Step 1: Substitute the limit at x = 0 and y = 0 into the function

$= \lim_{(x,y) \to (0,0)} \frac{x^4-34y^2}{x^2+17y^2}\\= \frac{0^4-34(0)^2}{0^2+17(0)^2}\\= \frac{0}{0} (indeterminate)$

Step 2: Substitute y = mx int o the function and simplify

$= \lim_{(x,mx) \to (0,0)} \frac{x^4-34(mx)^2}{x^2+17(mx)^2}\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^4-34m^2x^2}{x^2+17m^2x^2}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2(x^2-34m^2)}{x^2(1+17m^2)}\\\\\\= \lim_{(x,mx) \to (0,0)} \frac{x^2-34m^2}{1+17m^2}\\$

$= \frac{0^2-34m^2}{1+17m^2}\\\\= \frac{34m^2}{1+17m^2}\\\\$

<em>Since there are still variable 'm' in the resulting function, this shows that the limit of the function does not exist, Hence, the function DNE</em>

4 0

3 years ago

What is the solution set of (x - 2)(x - 3) = 2?.

Zinaida [17]

The solution set is X=1 and x=4

3 0

3 years ago

3 1/3 - 2 7/12 Please help me sorry its a mixed number

Black_prince [1.1K]

Answer:

it is 0.75

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which is the equation of a parabola with vertex (0, 0), that opens downward and has a focal width of 6?

Deffense [45]

Answer:Ambitious

Vertex: V=(0,0)=(h,k)→h=0, k=0

Opens downward:

(x-h)^2=4p(y-k)

Width focal: p=-6<0 (donwnward)

Replacing h=0, k=0 and p=-6 in the equation above:

(x-0)^2=4(-6)(y-0)

x^2=-24y

Answer: The equation of the parabola is x^2=-24y

7 0

3 years ago