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yan [13]
3 years ago
6

7 + 14 greatest common factor

Mathematics
2 answers:
boyakko [2]3 years ago
8 0

Answer:

The greatest common factor is 21,

Step-by-step explanation:

Find the prime factors of each term in order to find the greatest common factor (GCF).

Stels [109]3 years ago
8 0
Therefore, GCF = 7

So it would probably be 7
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In this combined function, the domain is all real numbers for x except?( x-2) / (x+5)
Sidana [21]
-5 because the denominator can’t equal zero
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3 years ago
Ryan took out a 66 month loan to pay for a 28500 car.if he paid 33829.50,in total at the end of the loan,find the interest rate
professor190 [17]

9514 1404 393

Answer:

  3.4%

Step-by-step explanation:

The total amount due is ...

  A = P(1 +rt/12) . . . . . principal P, annual rate r, t months

  33829.50 = 28500(1 +66/12r)

  1.187 = 1 +5.5r . . . . . divide by 28500, simplify

  0.185/5.5 = r = 0.034 = 3.4%

The interest rate on the loan is 3.4%.

3 0
3 years ago
PLEASE HELP ASAP!! WILL GIVE POINTS AND MARK BRAINLIEST!!!!!
Korvikt [17]

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6 0
3 years ago
Rate of change for y= 2/3x-48
tangare [24]

Answer:

2/3

Step-by-step explanation:

The rate of change is the same thing as the slope of a line

4 0
3 years ago
CALCULUS EXPERT WANTED
Vlad [161]

a. Use the mean value theorem. 16 falls between 12 and 20, so

v'(16)\approx\dfrac{v(20)-v(12)}{20-12}=\dfrac{240-200}8=5

(Don't forget your units - 5 m/min^2)

b. v(t) gives the Johanna's velocity at time t. The magnitude of her velocity, or speed, is |v(t)|. Integrating this would tell us the total distance she has traveled whilst jogging.

The Riemann sum approximates the integral as

\displaystyle\int_0^{40}|v(t)|\,\mathrm dt=12\cdot200+8\cdot240+4\cdot220+16\cdot150=7600

If you're not sure how this is derived: we're given 5 sample points, so we can cut the interval [0, 40] into 4 subintervals. The lengths of each subinterval are 12, 8, 4, and 16 (the distances between each sample point), and the height of the rectangle approximating the area under the plot of |v(t)| is determined by the value of v(t) at each sample point, 200, 240, |-220| = 220, and 150.

c. Bob's velocity is given by B(t), so his acceleration is given by B'(t). We have

B'(t)=3t^2-12t

and at t=5 his acceleration is B'(5)=15 m/min^2.

d. Bob's average velocity over [0, 10] is given by the difference quotient,

\dfrac{B(10)-B(0)}{10-0}=\dfrac{700-300}{10}=40 m/min

6 0
3 years ago
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